Python:我想装饰一个 MethodType 属性而不将属性类型更改为 FunctionType

Question

我想在不将 type(testObject) 更改为 FunctionType 的情况下实现以下功能:

import functools

class TestClass(object):
    def speak(self):
        print 'My Name is Test'

def hello_decorator(func):
    @functools.wraps(func)
    def hello_func(*args , **kwargs):   
        print 'Hello World'
        return func(*args , **kwargs)

    return hello_func

testObject = TestClass()

preDecoratedSpeak = hello_decorator(getattr(testObject , 'speak'))
setattr(testObject , 'speak' , preDecoratedSpeak)

testObject.speak()

print type(testObject.speak)

输出:

Hello World
My Name is Test
<type 'function'>

有没有办法在修饰方法的同时保持方法是 MethodType 实例化？

Answer 1

不幸的是 functools.wraps 在 python 2 中有一些缺点，其中许多在 python3 中已修复。

尝试使用 wrapt相反:

The wrapt module focuses very much on correctness. It therefore goes way beyond existing mechanisms such as functools.wraps() to ensure that decorators preserve introspectability, signatures, type checking abilities etc. The decorators that can be constructed using this module will work in far more scenarios than typical decorators and provide more predictable and consistent behaviour.