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python - Fabric - 测试与多台主机的 SSH 连接

转载 作者:行者123 更新时间:2023-11-28 22:38:16 24 4
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我有一个 Python 脚本,它使用结构库来测试与多个主机的 SSH 连接。我想将所有结果收集在一个列表中:

...
import fabric
from fabric.api import *

results = []

@parallel
def test_connection():
global results
try:
run('ls')
results += "%s: SUCCESS" % env.host
except Exception as e:
results += "%s: FAILURE. Exception: %e" % (env.host, e)

if __name__ == '__main__':
tasks.execute(test_connection)
print results

当我执行脚本时,我得到以下信息:

Traceback (most recent call last):
File "./test_ssh.py", line 99, in <module>
tasks.execute(test_connection)
File "/Library/Python/2.7/site-packages/fabric/tasks.py", line 387, in execute
multiprocessing
File "/Library/Python/2.7/site-packages/fabric/tasks.py", line 277, in _execute
return task.run(*args, **kwargs)
File "/Library/Python/2.7/site-packages/fabric/tasks.py", line 174, in run
return self.wrapped(*args, **kwargs)
File "./test_ssh.py", line 96, in test_connection
results += "%s: FAILURE. Exception: %e" % (env.host, e)
UnboundLocalError: local variable 'results' referenced before assignment

我认为这是因为 test_connection 运行它自己的上下文,所以它无法访问 results

还有其他方法可以收集我的结果吗?

最佳答案

诀窍在于您实际上可以从并行执行中返回结果:

@parallel
def test_connection():
try:
run('ls')
return True
except Exception:
return False

现在当你调用你的任务时,你会得到:

result = execute(test_connection)
results = [ ('HOST %s succeeded' % key) if value else ('HOST %s failed' % key) for key, value in result.items() ]

关于python - Fabric - 测试与多台主机的 SSH 连接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35781671/

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