ios - 如何与作为 ScrollView subview 的水平 ScrollView 交互？

Question

我有一个水平 ScrollView ，它是垂直 ScrollView 的 subview 。看起来垂直 ScrollView 正在拦截所有用户交互。我希望能够水平滚动水平 ScrollView 。我该怎么做？

这是我的一小段代码:

  UIScrollView *scrollView2 = [[UIScrollView alloc] initWithFrame:CGRectMake(0, 0,     self.view.width, 100)];

  scrollView2.contentSize = CGSizeMake(self.view.bounds.size.width + 400, 100);

  _scrollView.contentSize = CGSizeMake(self.view.width, 400);

  _scrollView = [[UIScrollView alloc] initWithFrame:CGRectMake(0, 0, self.view.bounds.size.width, self.view.height - 108)];

[self.view addSubview:_scrollView];

[_scrollView addSubview:scrollView2];

Answer 1

您可以子类化父 ScrollView 并覆盖 touchesShouldCancelInContentView: 以在 View 是子 ScrollView 时返回 NO。即；

MyScrollView.h

@interface MyScrollView: UIScrollView
@end

在 MyScrollView.m 中

@implementation MyScrollView


-(BOOL)touchesShouldCancelInContentView:(UIView *)touchedView{
      if(touchedView == _scrollView2){ //Get the reference of that child scroll view here
         return NO;
      }else{
         [super touchesShouldCancelInContentView:touchedView];
      }
}

那么你发布的代码应该是这样的:

UIScrollView *scrollView2 = [[UIScrollView alloc] initWithFrame:CGRectMake(0, 0,     self.view.width, 100)];

  scrollView2.contentSize = CGSizeMake(self.view.bounds.size.width + 400, 100);



  _myScrollView = [[MyScrollView alloc] initWithFrame:CGRectMake(0, 0, self.view.bounds.size.width, self.view.height - 108)];
  _myScrollView.contentSize = CGSizeMake(self.view.width, 400);


[_myScrollView addSubview:scrollView2];
[self.view addSubview:_myScrollView];