python - 从 Swagger 编辑器生成 Swagger 服务器(Python Flask)时出错

Question

我已使用 Swagger 编辑器手动生成我的 Swagger 规范文件并为 Python Flask 服务器生成文件。按照自述文件，我安装了 connexion，但是当我运行 python app.py 时，出现错误:ValueError:需要超过 1 个值才能解包。有什么想法吗？

下面是完整的堆栈跟踪:

No handlers could be found for logger "connexion.api"
Traceback (most recent call last):
  File "app.py", line 5, in <module>
    app.add_api('swagger.yaml')
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/app.py", line 144, in add_api
    debug=self.debug)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 127, in __init__
    self.add_paths()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 198, in add_paths
    six.reraise(*sys.exc_info())
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 187, in add_paths
    self.add_operation(method, path, endpoint, path_parameters)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 160, in add_operation
    resolver=self.resolver)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/operation.py", line 168, in __init__
    resolution = resolver.resolve(self)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/resolver.py", line 50, in resolve
    return Resolution(self.resolve_function_from_operation_id(operation_id), operation_id)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/resolver.py", line 71, in resolve_function_from_operation_id
    return self.function_resolver(operation_id)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/utils.py", line 106, in get_function_from_name
    module_name, attr_path1 = module_name.rsplit('.', 1)
ValueError: need more than 1 value to unpack

Answer 1

我也遇到过这个问题。据我所知，Swagger 生成的代码似乎假设您使用的是 Python 3。虽然 connexion 支持 Python 2.7 和 3.4+，但它在生成的 中确实需要一个 __init__.py 文件>python-flask-server/ 基本目录以及 controllers/ 子目录中，以用于 Python 2.7(Python 3.3 中引入了隐式命名空间包)。如果您在生成代码后创建这 2 个空文件，应该可以正常工作。如果 Swagger 生成器想要支持 Python 2.7(因为 connexion 允许)，它也只需要提供这些文件。