iphone - 关于 JSON 日期转换错误

Question

我得到 JSON 解析日期，我想使用 NSDateFormatter，但没有成功。

1.JSON获取控制台日志

IncidentReceiveTime = "/Date(1353914100000+0800)/";

2.我的代码

NSString *dateStr =[NSString stringWithFormat:@"%@",[[[DateSortArry objectAtIndex:0] objectForKey:@"IncidentReceiveTime"]stringByReplacingOccurrencesOfString:@"/" withString:@""]];
    NSLog(@"dateStr:%@",dateStr);

    NSDateFormatter *dateFormatter = [[NSDateFormatter alloc]init];
    [dateFormatter setLocale:[NSLocale currentLocale]];
    [dateFormatter setDateFormat:@"yyyy-MM-ddHH"];
    NSDate *date = [dateFormatter dateFromString:dateStr];
    NSLog(@"date:%@",date);

3.NSDateFormatter控制台日志

dateStr:Date(1361943694000+0800)
date:(null)

Answer 1

引用我的回答:

iPhone:How to convert Regular Expression into Date Format?

在这里，我在上面的链接中发布我的答案中的这段代码，好像万一将来上面的链接失效，那么这个答案就没有用了:

- (NSDate*) getDateFromJSON:(NSString *)dateString
{
    // Expect date in this format "/Date(1268123281843)/"
    int startPos = [dateString rangeOfString:@"("].location+1;
    int endPos = [dateString rangeOfString:@")"].location;
    NSRange range = NSMakeRange(startPos,endPos-startPos);
    unsigned long long milliseconds = [[dateString substringWithRange:range] longLongValue];
    NSLog(@"%llu",milliseconds);
    NSTimeInterval interval = milliseconds/1000;
    return [NSDate dateWithTimeIntervalSince1970:interval];
}

一旦你从上面的方法中得到了 NSDate 对象:

NSDateFormatter *dateForm = [[NSDateFormatter alloc] init];
[dateForm setDateFormat:@"yyyy-MM-dd hh:mm:ss"];
NSString *dateStr = [dateForm stringFromDate:<YourNSDateObject>];
[dateForm setDateFormat:@"<Your Desired Date Format>"];
NSDate *desireddate = [dateForm dateFromString:dateStr];

希望这对您有所帮助。