python - IBM WebSphere Application Server wsadmin 在脚本中仅返回 6 个结果中的第一个结果

Question

当尝试获取 WebSphere Application Server 中应用程序的状态时，我希望返回多个 mbean。然而，WAS 似乎只返回第一个结果并丢弃其余结果。

[wasadmin@servername01 ~]$ Run_wsadmin.sh -f wsadmin_Check_App_Status.py
WASX7209I: Connected to process "dmgr" on node PRDDMGR using SOAP connector;  The type of process is: DeploymentManager
WASX7026W: String "type=Application,name=AMTApp,*" corresponds to 6 different MBeans; returning first one.

我正在运行的脚本如下所示:

app_name = AppName
app_status = AdminControl.completeObjectName('type=Application,name=' + app_name + ',*').split('\n')

for status in app_status :
  print( status )
# end of For status in app_status

WebSphere 中是否有一些设置，或者我是否需要将一些特殊的库导入到我的脚本中？

Answer 1

根据AdminControl.completeObjectName()的文档

Use the completeObjectName command to create a string representation of a complete ObjectName value that is based on a fragment. This command does not communicate with the server to find a matching ObjectName value. If the system finds several MBeans that match the fragment, the command returns the first one.

因此该函数的行为符合预期。

改为:
在这种情况下，听起来您想使用 AdminControl.queryNames()，它是为返回与您的查询匹配的结果列表而构建的。

例如:

app_name = AppName
app_status = AdminControl.queryNames('type=Application,name=' + app_name + ',*').split('\n')

for status in app_status :
  print( status )

来源:Commands for the AdminControl object using wsadmin scripting