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python - 无法在 Python 3.5 中子类化多处理队列

转载 作者:行者123 更新时间:2023-11-28 22:33:53 26 4
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我的最终目标是将 stdout 从几个子进程重定向到一些队列,并将它们打印到某个地方(可能在一个小 GUI 中)。

第一步是将 Queue 子类化为一个行为类似于 stdout 的对象。但这就是我被困的地方。在 Python v3.5 中子类化多处理 Queue 似乎是不可能的。

# This is a Queue that behaves like stdout
# Unfortunately, doesn't work in Python 3.5 :-(
class StdoutQueue(Queue):
def __init__(self,*args,**kwargs):
Queue.__init__(self,*args,**kwargs, ctx='')

def write(self,msg):
self.put(msg)

def flush(self):
sys.__stdout__.flush()

我在下面的帖子中找到了这个片段(可能当时 Python 3.5 还不存在):Python multiprocessing redirect stdout of a child process to a Tkinter Text

在 Python v3.5 中,当子类化 multiprocessing Queue 类时,您会偶然发现奇怪的错误消息。我发现了两个描述该问题的错误报告:

https://bugs.python.org/issue21367

https://bugs.python.org/issue19895

我有两个问题:

  1. 假设我想坚持使用 Python v3.5 - 转到以前的版本并不是一个真正的选择。我可以使用什么解决方法以某种方式对多处理队列进行子类化?
  2. 如果我升级到 Python v3.6,错误是否仍然存在?

编辑:

当您尝试对此处找到的 Queue 类进行子类化时,存在一个已知问题:

from multiprocessing import Queue    # <- known issue: you cannot subclass
# this Queue class, because it is
# not a genuine python class.

但以下应该有效:

from multiprocessing.queues import Queue   # <- from this Queue class, you
# should be able to make a
# subclass. But Python 3.5
# refuses :-(

遗憾的是,即使这样在 Python v3.5 中也不起作用。您收到以下错误:

    C:\Users\..\myFolder > python myTest.py

Traceback (most recent call last):
File "myTest.py", line 49, in <module>
q = StdoutQueue()
File "myTest.py", line 22, in __init__
super(StdoutQueue,self).__init__(*args,**kwargs)
TypeError: __init__() missing 1 required keyword-only argument: 'ctx'

编辑:

感谢 Darth Kotik 解决了这个问题!这是完整的代码,更新了他的解决方案。现在可以了。

import sys
import time
import multiprocessing as mp
import multiprocessing.queues as mpq
from threading import Thread
from tkinter import *

'''-------------------------------------------------------------------'''
''' SUBCLASSING THE MULTIPROCESSING QUEUE '''
''' '''
''' ..and make it behave as a general stdout io '''
'''-------------------------------------------------------------------'''
# The StdoutQueue is a Queue that behaves like stdout.
# We will subclass the Queue class from the multiprocessing package
# and give it the typical stdout functions.
#
# (1) First issue
# Subclassing multiprocessing.Queue or multiprocessing.SimpleQueue
# will not work, because these classes are not genuine
# python classes.
# Therefore, you need to subclass multiprocessing.queues.Queue or
# multiprocessing.queues.SimpleQueue . This issue is known, and is not
# the reason for asking this question. But I mention it here, for
# completeness.
#
# (2) Second issue
# There is another problem that arises only in Python V5 (and beyond).
# When subclassing multiprocessing.queues.Queue, you have to provide
# a 'multiprocessing context'. Not doing that, leads to an obscure error
# message, which is in fact the main topic of this question. Darth Kotik
# solved it.
# His solution is visible in this code:
class StdoutQueue(mpq.Queue):

def __init__(self,*args,**kwargs):
ctx = mp.get_context()
super(StdoutQueue, self).__init__(*args, **kwargs, ctx=ctx)

def write(self,msg):
self.put(msg)

def flush(self):
sys.__stdout__.flush()


'''-------------------------------------------------------------------'''
''' TEST SETUP '''
'''-------------------------------------------------------------------'''

# This function takes the text widget and a queue as inputs.
# It functions by waiting on new data entering the queue, when it
# finds new data it will insert it into the text widget.
def text_catcher(text_widget,queue):
while True:
text_widget.insert(END, queue.get())

def test_child(q):
# This line only redirects stdout inside the current process
sys.stdout = q
# or sys.stdout = sys.__stdout__ if you want to print the child to the terminal
print('child running')

def test_parent(q):
# Again this only redirects inside the current (main) process
# commenting this like out will cause only the child to write to the widget
sys.stdout = q
print('parent running')
time.sleep(0.5)
mp.Process(target=test_child,args=(q,)).start()

if __name__ == '__main__':
gui_root = Tk()
gui_txt = Text(gui_root)
gui_txt.pack()
q = StdoutQueue()
gui_btn = Button(gui_root, text='Test', command=lambda:test_parent(q),)
gui_btn.pack()

# Instantiate and start the text monitor
monitor = Thread(target=text_catcher,args=(gui_txt,q))
monitor.daemon = True
monitor.start()

gui_root.mainloop()

最佳答案

>>> import multiprocessing
>>> type(multiprocessing.Queue)
<class 'method'>
AttributeError: module 'multiprocessing' has no attribute 'queues'
>>> import multiprocessing.queues
>>> type(multiprocessing.queues.Queue)
<class 'type'>

如您所见,multiprocessing.Queue 只是multiprocessing.queues.Queue 类的构造方法。如果你想创建一个子类,只需执行 class MyQueue(multiprocessing.queues.Queue)

你可以看到这个方法的来源here

编辑:好的。我现在知道你的问题了。正如您在上面的链接中看到的,multiprocessing.Queuectx 参数传递给 Queue。所以我设法通过自己在 __init__ 方法中完成它来使其工作。我不完全明白 BaseContext 对象应该在哪里获得 _name 属性,所以我手动传递了它。

def __init__(self,*args,**kwargs):
from multiprocessing.context import BaseContext
ctx = BaseContext()
ctx._name = "Name"
super(StdoutQueue,self).__init__(*args,**kwargs, ctx=ctx)

EDIT2:原来的文档有一些关于上下文的信息 here .因此,您可以像我那样手动创建它

import multiprocessing
ctx = multiprocessing.get_context()

它将创建适当的上下文并设置 _name(在您的特定情况下为“fork”),您可以将其传递给您的队列。

关于python - 无法在 Python 3.5 中子类化多处理队列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39496554/

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