python - 从 for 循环中查找前 9 个数字的平均值，然后是接下来的 9 个数字，依此类推

Question

我有一个 for 循环，它给我以下输出。

0.53125
0.4375
0.546875
0.578125
0.75
0.734375
0.640625
0.53125
0.515625
0.828125
0.5
0.484375
0.59375
0.59375
0.734375
0.71875
0.609375
0.484375
.
.
.

如何找到前 9 个值、接下来的 9 个值等的平均值，并将它们存储到像 [0.58,0.20,...] 这样的列表中？我尝试了很多东西，但这些值似乎不正确。这样做的正确方法是什么？

我做了什么:

matchedRatioList = []
matchedRatio = 0
i = 0
for feature in range(90):
    featureToCompare = featuresList[feature]
    number = labelsList[feature]
    match = difflib.SequenceMatcher(None,featureToCompare,imagePixList)
    matchingRatio = match.ratio()
    print(matchingRatio)
    matchedRatio += matchingRatio
    if i == 8:
        matchedRatioList.append(matchedRatio / 9)
        i = 0
        matchedRatio = 0
    i += 1

Answer 1

获得数字列表后，您可以使用列表理解计算每组 9 个数字的平均值:

from statistics import mean

numbers = [0.53125, 0.4375, 0.546875, 0.578125, 0.75, 0.734375, 0.640625,
           0.53125, 0.515625, 0.828125, 0.5, 0.484375, 0.59375, 0.59375, 
           0.734375, 0.71875, 0.609375, 0.484375]

group_len = 9
matched_ratios = [mean(group) for group in [numbers[i:i+group_len] 
                  for i in range(0, len(numbers), group_len)]]
print(matched_ratios)
# [0.5850694444444444, 0.6163194444444444]