java - Android - 当我在设备上运行它时无法访问网络服务，但使用 AVD 它可以正常工作。为什么？

Question

我有这个位置的网络服务:

<wsdlsoap:address location="http://app.example.com:8080/WSTest/services/Hello"/>

我想通过我的 Android 应用程序访问此网络服务。我这样做:

private class ConnectTask extends AsyncTask<String, Void, String> {

        @Override
        protected String doInBackground(String... params) {

            private final String NAMESPACE = "http://ws.audiomobil.com";
            private final String URL = "http://app.example.com:8080/WSTest/services/Hello?wsdl";
            private final String SOAP_ACTION = "http://ws.audiomobil.com/hello";
            private final String METHOD_NAME = "hello";

            try {
                SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

                String firstName = "Android";
                String lastName = "Program";
/*
                // Pass value for fname variable of the web service
                PropertyInfo fnameProp = new PropertyInfo();
                fnameProp.setName("fname");         // Define the variable name in the web service method
                fnameProp.setValue(firstName);      // Define value for fname variable
                fnameProp.setType(String.class);    // Define the type of thevariable
                request.addProperty(fnameProp);     // Pass properties to thevariable

                // Pass value for lname variable of the web service
                PropertyInfo lnameProp = new PropertyInfo();
                lnameProp.setName("lname");
                lnameProp.setValue(lastName);
                lnameProp.setType(String.class);
                request.addProperty(lnameProp);
*/
                SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
                envelope.dotNet = true;
                envelope.setOutputSoapObject(request);
                HttpTransportSE androidHttpTransport = new HttpTransportSE(URL,60000);

                try {
                    androidHttpTransport.call(SOAP_ACTION, envelope);
                    SoapPrimitive response = (SoapPrimitive) envelope.getResponse();
                    String s = response.toString();
                    System.out.println("WS: " + s);
                } catch (Exception e) {
                    System.out.println(e);
                    e.printStackTrace();
                }
            } catch (Exception e) {
                System.out.println(e);
                e.printStackTrace();
            }
            return null;

        }
    }

++++++编辑我的网络服务类是这样的:

public class Hello {
    public String hello(String fname, String lname){
         return "Hello";
     }
}

++++++++

当我在我的 AVD 模拟器 Android 4.0.3 上运行它时，它工作正常。它可以访问网络服务，我得到了响应。

但是当我在我的设备版本 4.0.3 上运行它时，它无法正常工作。它在此时停止:androidHttpTransport.call(SOAP_ACTION, envelope);

它会抛出一个 XMLPullParserException。这是 logcat:

    01-23 11:24:36.959: I/System.out(8172): org.xmlpull.v1.XmlPullParserException: 

unterminated entity ref (position:TEXT @1:86 in java.io.InputStreamReader@4188c258) 

我真的不知道这是怎么发生的。谁能帮帮我？

Answer 1

我认为您缺少 xml 版本标记。调用前尝试设置xml版本标签

androidHttpTransport.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"utf-8\"?>");
androidHttpTransport.call(SOAP_ACTION, envelope);

示例代码:

public static String webServiceForScriptTimeLimit() {
        String scriptTimeLimitResponse = null;
        try {
            SoapObject request = new SoapObject(NAMESPACE,
                    SCRIPT_TIMELIMIT_METHOD_NAME);
            SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                    SoapEnvelope.VER11);
            envelope.dotNet = true;
            envelope.implicitTypes = true;
            envelope.enc = SoapSerializationEnvelope.ENC2003;
            envelope.xsd = SoapEnvelope.XSD;
            envelope.xsi = SoapEnvelope.XSI;
            envelope.setOutputSoapObject(request);
            envelope.setAddAdornments(false);
            HttpTransportSE ht = new HttpTransportSE(SOAP_ADDRESS);
            ht.debug = true;
            ht.call(SOAP_ACTION_TIME_LIMIT, envelope);
            final SoapPrimitive response = (SoapPrimitive) envelope
                    .getResponse();
            scriptTimeLimitResponse = response.toString();

        }

        catch (Exception ex) {
            FileLog.logInfo(
                    "Exception ---> WS_ERROR ---> WebServiceUtility: webServiceForScriptTimeLimit() - "
                            + ex.toString(), 0);
        }
        return scriptTimeLimitResponse;
    }