python - 如何在 'n' 个逗号后加入 python 中的列表？

Question

我怎样才能得到像这样的大列表:

line = ['8', '2', '22', '97', '38', '15', '0', '40', '0', '75', '4', '5', '7', '78', '52', '12', '50', '77', '91', '8', '49', '49', '99', '40', '17', '81', '18', '57', '60', '87', '17', '40', '98', '43', '69', '48', '4', '56', '62', '0', '81', '49', '31', '73', '55', '79', '14', '29', '93', '71', '40', '67', '53', '88', '30', '3', '49', '13', '36', '65', '52', '70', '95', '23', '4', '60', '11', '42', '69', '24', '68', '56', '1', '32', '56', '71', '37', '2', '36', '91', '22', '31', '16', '71', '51', '67', '63', '89', '41', '92', '36', '54', '22', '40', '40', '28', '66', '33', '13', '80', '24', '47', '32', '60', '99', '3', '45', '2', '44', '75', '33', '53', '78', '36', '84', '20', '35', '17', '12', '50', '32', '98', '81', '28', '64', '23', '67', '10', '26', '38', '40', '67', '59', '54', '70', '66', '18', '38', '64', '70', '67', '26', '20', '68', '2', '62', '12', '20', '95', '63', '94', '39', '63', '8', '40', '91', '66', '49', '94', '21', '24', '55', '58', '5', '66', '73', '99', '26', '97', '17', '78', '78', '96', '83', '14', '88', '34', '89', '63', '72', '21', '36', '23', '9', '75', '0', '76', '44', '20', '45', '35', '14', '0', '61', '33', '97', '34', '31', '33', '95', '78', '17', '53', '28', '22', '75', '31', '67', '15', '94', '3', '80', '4', '62', '16', '14', '9', '53', '56', '92', '16', '39', '5', '42', '96', '35', '31', '47', '55', '58', '88', '24', '0', '17', '54', '24', '36', '29', '85', '57', '86', '56', '0', '48', '35', '71', '89', '7', '5', '44', '44', '37', '44', '60', '21', '58', '51', '54', '17', '58', '19', '80', '81', '68', '5', '94', '47', '69', '28', '73', '92', '13', '86', '52', '17', '77', '4', '89', '55', '40', '4', '52', '8', '83', '97', '35', '99', '16', '7', '97', '57', '32', '16', '26', '26', '79', '33', '27', '98', '66', '88', '36', '68', '87', '57', '62', '20', '72', '3', '46', '33', '67', '46', '55', '12', '32', '63', '93', '53', '69', '4', '42', '16', '73', '38', '25', '39', '11', '24', '94', '72', '18', '8', '46', '29', '32', '40', '62', '76', '36', '20', '69', '36', '41', '72', '30', '23', '88', '34', '62', '99', '69', '82', '67', '59', '85', '74', '4', '36', '16', '20', '73', '35', '29', '78', '31', '90', '1', '74', '31', '49', '71', '48', '86', '81', '16', '23', '57', '5', '54', '1', '70', '54', '71', '83', '51', '54', '69', '16', '92', '33', '48', '61', '43', '52', '1', '89', '19', '67', '48']

并使其在每第 20 个数字后用分号和空格连接它，(';') 并且每隔一次它只用空格连接它？

除了更大之外，它看起来像这样:

“8 22 2 97；58 33 44 82；86...”等等。

Answer 1

易于理解列表和 2 个嵌套的 str.join:

"; ".join([" ".join(line[i:i+20]) for i in range(0,len(line),20)])

您将列表切片以每 20 个元素作为内部部分，创建以空格分隔的字符串列表，然后使用“外部”分隔符加入结果列表。

即使列表大小不能被 20 整除，它也能工作并且速度超快

(请注意，我强制为外部 join 创建列表，因为 join 无论如何都需要创建一个列表。在这种情况下，它比通过生成器理解更快)