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python - 如何发出 pycurl http2 请求?

转载 作者:行者123 更新时间:2023-11-28 22:29:53 26 4
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我正在尝试通过 pycurl 发出 http2 请求。我已经安装了 libcurl 需要的 nghttp2 c 库,我可以用 curl 做一个 http2 请求。

我用 pycurl 尝试过这样的事情:

import pycurl
import cStringIO


if __name__ == '__main__':
c = pycurl.Curl()

buf = cStringIO.StringIO()

c = pycurl.Curl()
c.setopt(c.URL, 'https://nghttp2.org')
c.setopt(pycurl.HTTP_VERSION, pycurl.VERSION_HTTP2)
c.setopt(c.WRITEFUNCTION, buf.write)
c.setopt(pycurl.VERBOSE, 1)
c.perform()

buf.close()

我得到的输出是:

* Rebuilt URL to: https://nghttp2.org/
* Trying 106.186.112.116...
* Connected to nghttp2.org (106.186.112.116) port 443 (#0)
* Cipher selection: ALL:!EXPORT:!EXPORT40:!EXPORT56:!aNULL:!LOW:!RC4:@STRENGTH
* successfully set certificate verify locations:
* CAfile: /etc/ssl/certs/ca-certificates.crt
CApath: none
* NPN, negotiated HTTP1.1
* SSL connection using TLSv1.2 / ECDHE-RSA-AES256-GCM-SHA384
* Server certificate:
* subject: CN=nghttp2.org
* start date: Jan 21 22:58:00 2017 GMT
* expire date: Apr 21 22:58:00 2017 GMT
* subjectAltName: nghttp2.org matched
* issuer: C=US; O=Let's Encrypt; CN=Let's Encrypt Authority X3
* SSL certificate verify ok.
> GET / HTTP/1.1
Host: nghttp2.org
User-Agent: PycURL/7.43.0 libcurl/7.46.0 OpenSSL/1.0.1f zlib/1.2.8 libidn/1.28 nghttp2/1.21.0-DEV librtmp/2.3
Accept: */*
Connection: Upgrade, HTTP2-Settings
Upgrade: h2c
HTTP2-Settings:

< HTTP/1.1 200 OK
< Date: Tue, 14 Mar 2017 13:33:48 GMT
< Content-Type: text/html
< Last-Modified: Sun, 26 Feb 2017 12:19:00 GMT
< Etag: "58b2c7b4-19e1"
< Accept-Ranges: bytes
< Content-Length: 6625
< X-Backend-Header-Rtt: 0.001418
< Strict-Transport-Security: max-age=31536000
< Server: nghttpx
< Via: 2 nghttpx
< x-frame-options: SAMEORIGIN
< x-xss-protection: 1; mode=block
< x-content-type-options: nosniff
<
* Connection #0 to host nghttp2.org left intact

我在这个请求中做错了什么?

编辑:根据评论,我确保 pycurl 使用 OpenSSL/1.0.2k。现在 User-Agent header 如下所示:User-Agent: PycURL/7.43.0 libcurl/7.46.0 OpenSSL/1.0.2k zlib/1.2.11 libidn/1.28 nghttp2/1.21.0-DEV librtmp/2.3 但我得到了相同的结果如上。

最佳答案

似乎 pycurl 脚本使用了错误的 http 版本常量。正确的是 c.setopt(pycurl.HTTP_VERSION, pycurl.CURL_HTTP_VERSION_2_0)

关于python - 如何发出 pycurl http2 请求?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42787564/

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