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java - 尝试在 tomcat 服务器上配置 hibernate 时出现命名异常

转载 作者:行者123 更新时间:2023-11-28 22:24:19 26 4
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EDIT: A solution to this problem has been found, the issue was that in persistence.xml, the data-source-name needed to be prefixed with java:comp/env/ like so: java:comp/env/jdbc/TSDB

我知道这是一个有据可查的问题,但是,经过多次不同的尝试和大量阅读后,我仍然无法配置 Hibernate 使用的数据源。

我正在尝试开发一个使用 hibernate 模式连接到 MySQL 服务器的 Tomcat 应用服务器。

我使用的 Eclipse 版本:2018-12 (4.10.0) hibernate :5.4.1.FinalMysql 连接器:8.0.14服务器:Apache Tomcat/9.0.14

数据源在server.xml中定义:

  <GlobalNamingResources>

<Resource auth="Container" driverClassName="com.mysql.jdbc.Driver" maxTotal="100"
maxIdle="30" maxWaitMillis="10000" minIdle="5" name="jdbc/TSDB" password="PASSWORD"
type="javax.sql.DataSource" url="jdbc:mysql://localhost:3306/tstest?allowPublicKeyRetrieval=true" username="USERNAME"/>


</GlobalNamingResources>

网络.xml:

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd" id="WebApp_ID" version="4.0">
<resource-ref>
<res-ref-name>jdbc/TSDB</res-ref-name>
<res-type>javax.sql.DataSource</res-type>
<res-auth>Container</res-auth>
</resource-ref>
</web-app>

上下文.xml:

<Context>
<ResourceLink name="jdbc/TSDB" global="jdbc/TSDB" type="javax.sql.DataSource" />
</Context>

持久性.xml:

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1"
xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="TsPersistence" transaction-type="JTA">

<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<jta-data-source>jdbc/TSDB</jta-data-source>

<!-- Entity Classes Mappings -->
<class>com.ts.hibernate.entities.User</class>
<!-- EO Entity Classes Mappings -->

<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect"/>
</properties>
</persistence-unit>
</persistence>

然后当我尝试在网络监听器中创建一个实体管理器时:

@WebListener
public class HibernateSessionFactoryListener implements ServletContextListener {
public final Logger logger = LogManager.getLogger(HibernateSessionFactoryListener.class);

public void contextInitialized(ServletContextEvent servletContextEvent) {


EntityManagerFactory entityManagerFactory = Persistence.createEntityManagerFactory("TsPersistence");
servletContextEvent.getServletContext().setAttribute("EntityManagerFactory", entityManagerFactory);

logger.info("Entity Manager Configured Successfully!");
}

我收到以下错误:

Feb 15, 2019 12:00:55 AM org.apache.catalina.core.StandardContext listenerStart
SEVERE: Exception sending context initialized event to listener instance of class [com.ts.hibernate.listeners.HibernateSessionFactoryListener]
javax.persistence.PersistenceException: Explicit persistence provider error(s) occurred for "TsPersistence" after trying the following discovered implementations: org.hibernate.jpa.HibernatePersistenceProvider, org.apache.openjpa.persistence.PersistenceProviderImpl from provider: org.hibernate.jpa.HibernatePersistenceProvider
at javax.persistence.Persistence.createPersistenceException(Persistence.java:244)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:186)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:72)
at com.ts.hibernate.listeners.HibernateSessionFactoryListener.contextInitialized(HibernateSessionFactoryListener.java:45)
at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4663)
at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5131)
at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:183)
at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1382)
at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1372)
at java.base/java.util.concurrent.FutureTask.run(FutureTask.java:264)
at org.apache.tomcat.util.threads.InlineExecutorService.execute(InlineExecutorService.java:75)
at java.base/java.util.concurrent.AbstractExecutorService.submit(AbstractExecutorService.java:140)
at org.apache.catalina.core.ContainerBase.startInternal(ContainerBase.java:907)
at org.apache.catalina.core.StandardHost.startInternal(StandardHost.java:831)
at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:183)
at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1382)
at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1372)
at java.base/java.util.concurrent.FutureTask.run(FutureTask.java:264)
at org.apache.tomcat.util.threads.InlineExecutorService.execute(InlineExecutorService.java:75)
at java.base/java.util.concurrent.AbstractExecutorService.submit(AbstractExecutorService.java:140)
at org.apache.catalina.core.ContainerBase.startInternal(ContainerBase.java:907)
at org.apache.catalina.core.StandardEngine.startInternal(StandardEngine.java:262)
at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:183)
at org.apache.catalina.core.StandardService.startInternal(StandardService.java:423)
at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:183)
at org.apache.catalina.core.StandardServer.startInternal(StandardServer.java:933)
at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:183)
at org.apache.catalina.startup.Catalina.start(Catalina.java:637)
at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at java.base/jdk.internal.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.base/java.lang.reflect.Method.invoke(Method.java:566)
at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:350)
at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:492)
Caused by: org.hibernate.service.spi.ServiceException: Unable to create requested service [org.hibernate.engine.jdbc.env.spi.JdbcEnvironment]
at org.hibernate.service.internal.AbstractServiceRegistryImpl.createService(AbstractServiceRegistryImpl.java:275)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:237)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:214)
at org.hibernate.id.factory.internal.DefaultIdentifierGeneratorFactory.injectServices(DefaultIdentifierGeneratorFactory.java:152)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.injectDependencies(AbstractServiceRegistryImpl.java:286)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:243)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:214)
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.<init>(InFlightMetadataCollectorImpl.java:175)
at org.hibernate.boot.model.process.spi.MetadataBuildingProcess.complete(MetadataBuildingProcess.java:118)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.metadata(EntityManagerFactoryBuilderImpl.java:903)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:934)
at org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:56)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:152)
... 32 more
Caused by: org.hibernate.engine.jndi.JndiException: Unable to lookup JNDI name [jdbc/TSDB]
at org.hibernate.engine.jndi.internal.JndiServiceImpl.locate(JndiServiceImpl.java:100)
at org.hibernate.engine.jdbc.connections.internal.DatasourceConnectionProviderImpl.configure(DatasourceConnectionProviderImpl.java:98)
at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:107)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:246)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:214)
at org.hibernate.engine.jdbc.env.internal.JdbcEnvironmentInitiator.buildJdbcConnectionAccess(JdbcEnvironmentInitiator.java:145)
at org.hibernate.engine.jdbc.env.internal.JdbcEnvironmentInitiator.initiateService(JdbcEnvironmentInitiator.java:66)
at org.hibernate.engine.jdbc.env.internal.JdbcEnvironmentInitiator.initiateService(JdbcEnvironmentInitiator.java:35)
at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.initiateService(StandardServiceRegistryImpl.java:101)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.createService(AbstractServiceRegistryImpl.java:263)
... 44 more
Caused by: javax.naming.NameNotFoundException: Name [jdbc/TSDB] is not bound in this Context. Unable to find [jdbc].
at org.apache.naming.NamingContext.lookup(NamingContext.java:817)
at org.apache.naming.NamingContext.lookup(NamingContext.java:159)
at org.apache.naming.SelectorContext.lookup(SelectorContext.java:140)
at java.naming/javax.naming.InitialContext.lookup(InitialContext.java:413)
at org.hibernate.engine.jndi.internal.JndiServiceImpl.locate(JndiServiceImpl.java:97)

我需要创建任何其他配置吗?任何帮助将不胜感激,谢谢!

最佳答案

server.xml 文件中声明的 GlobalNamingResource 元素等同于 ( Docs ) resource-refweb.xml 文件。我会说删除 web.xml

里面的那个
<resource-ref>
<res-ref-name>jdbc/TSDB</res-ref-name>
<res-type>javax.sql.DataSource</res-type>
<res-auth>Container</res-auth>
</resource-ref>

关于java - 尝试在 tomcat 服务器上配置 hibernate 时出现命名异常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54700270/

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