ios - 如何正确生成时间戳

Question

我有一个方法可以创建 long long integer 格式的时间戳例如:1386752892

+ (NSNumber *)currentTimestampWithLongLongFormat
{
    double timeStamp = ceil([[NSDate date] timeIntervalSince1970] * 1000);

    NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
    [formatter setGeneratesDecimalNumbers:false];
    NSNumber *timeNumber = [NSNumber numberWithDouble:timeStamp];
    NSString *timeString = [formatter stringFromNumber:timeNumber];

    // NSTimeInterval is defined as double
    return [NSNumber numberWithLongLong:[timeString longLongValue]];
}

但这会生成13位数字例如:1386752811802

如何解决问题并生成正确格式的数字？

Answer 1

 int timestamp = [[NSDate date] timeIntervalSince1970];