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java - 请求的资源不可用 Java REST API

转载 作者:行者123 更新时间:2023-11-28 22:17:50 26 4
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我创建了一个简单的 Rest Api,它返回存储在数据库中的 id,但是当我在浏览器中键入 url 时,它显示错误

这是我在做的事情

package com.comicsmv.api;

//Imports here

@Path("/files")
public class Api {

private static final String SERVER_UPLOAD_LOCATION_FOLDER = "/home/hassan/Downloads/";

/**
* Upload a File
*
* @throws IOException
*/

@POST
@Path("/upload")
@Consumes(MediaType.APPLICATION_JSON)
@Produces(MediaType.APPLICATION_JSON)
public Response responseMsg(String obj) {
String object = obj;

JSONObject jobj = null;
try {
jobj = new JSONObject(object);
} catch (JSONException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
String api_key = null;
try {
api_key = jobj.getString("api_key");
} catch (JSONException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
File f = new File("home/hassan/api_key.txt");
String file_name = f.getName();
String key = readFile(file_name);
if (api_key != key) {
return Response.status(400).entity("Api key does not found/match")
.build();
} else {
try {
String img = jobj.getString("image");

BufferedImage image = null;
byte[] imageByte;

String file_path = System.getProperty("user.dir");
File directory = new File(file_path + "/uploads");
boolean exists = directory.exists();
if (!exists) {
directory.mkdir();
}

try {
BASE64Decoder decoder = new BASE64Decoder();
imageByte = decoder.decodeBuffer(img);
ByteArrayInputStream bis = new ByteArrayInputStream(
imageByte);
image = ImageIO.read(bis);
bis.close();
java.util.Date date = new java.util.Date();
String outputfile = directory.toString() + "/"
+ new Timestamp(date.getTime()) + ".png";
// System.out.println(outputfile);
ImageIO.write(image, "png", new File(outputfile));

} catch (Exception e) {
e.printStackTrace();
}

} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return Response.status(200).entity(obj).build();
}
}
}

这里是 web.xml 文件

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>Comicsmv_Api</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>jersey-helloworld-serlvet</servlet-name>
<servlet-class>
com.sun.jersey.spi.container.servlet.ServletContainer
</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.comicsmv.api</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
<servlet-name>jersey-helloworld-serlvet</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>

但是当我输入类似 (localhost:8080/Comicsmv_Api/rest/files/upload) 的 url 时,它会显示 404 状态,表示请求的源不可用。

最佳答案

问题是:

没有匹配此请求的 REST API:

GET localhost:8080/Comicsmv_Api/rest/files/upload

你拥有的是:

POST localhost:8080/Comicsmv_Api/rest/files/upload
+ { JSON payload }

记住浏览器总是发送 GET 请求。要发送其他 HTTP 方法请求,请使用如下工具,您可以选择所有 HTTP 方法:

  • > postman ( Chrome 扩展)
  • > restclient (添加 Firefox 调试器)
  • > soapUI (开源网络服务测试应用程序)

关于java - 请求的资源不可用 Java REST API,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37585178/

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