python - 选择向前看和向后看之间的部分

Question

我想从工作信息中检索数据并输出结构化的 json，一个工作详细信息如下

In [185]: text = """Company
     ...: 
     ...: Stack Overflow
     ...: 
     ...: Job Title
     ...: 
     ...: Student
     ...: 
     ...: Job Description
     ...: 
     ...: Our client is providing the innovative technologies, ....
     ...: 
     ...: Requirements
     ...: .....
     ...: About the Company
     ...: 
     ...: At ...., we are a specialized ..
     ...: 
     ...: Contact Info
     ...: ...
     ...: """

我尝试用命名组提取

jobs_regex = re.compile(r"""
(?P<company>Company(?<=Company).*(?:=Job Title))
# the parts between "Company and Job Title
(?P<job_title>Job Title(?<=Job Title).*(?:=Job Description))
# the parts between "Job Title and Job Description
....
""",re.VERBOSE)

但是，当我运行它时得到空列表

In [188]: jobs_regex.findall(text)
Out[188]: []

如何解决环视问题 (?:) (?<=)？

Answer 1

我不知道你是否真的想使用 lookarounds 但这里有一个不使用它们的简单解决方案:

Company(?P<company>.*)Job Title(?P<job_title>.*)Job Description