ios - 搜索栏不显示结果

Question

我在 UISearch 栏上练习。它应该显示它的范围，但我不起作用。我将搜索栏 View Controller 连接到原始 View Controller 。我检查了控制台(我放置了 NSLog 以查看 NSPredicate 属性是否有效)，它显示了结果，但没有显示在屏幕上。请任何建议。谢谢:)

#import "ViewController.h" #import "detailViewController.h"//我意识到这不是好的做法。第一个字母要大写

@interface ViewController ()
{
    NSMutableArray *_recipes;
    NSString *_recipeName;
    NSArray *_searchResults;
}
@end

@implementation ViewController

- (void)viewDidLoad
{
    [super viewDidLoad];
    // Do any additional setup after loading the view, typically from a nib.

    self.tableView.delegate = self;
    self.tableView.dataSource = self;
    _recipes = [NSMutableArray arrayWithObjects:@"Egg Benedict",@"Mushroom Risotto",@"Full Breakfast", @"Hamburger",@"Ham and Egg Sandwich", @"Cream Brelee",@"White Chocolate Donut",@"Starbucks Coffee",@"Vegetable Curry", @"Instant Noodle With Egg",@"Noodle with BBQ Pork", @"Japanese Noodle with Pork",@"Green Tea", @"Thai shripm Cake", @"Angry Birds Cake",@"Ham and Cheese Panini",nil];

}

- (void)didReceiveMemoryWarning
{
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}

# pragma mark Dlegate method

// Data source protocol

- (NSInteger)tableView:(UITableView *)tableview numberOfRowsInSection:(NSInteger)section
{
    if(self.tableView == self.searchDisplayController.searchResultsTableView)
    {
        return [_searchResults count];
    }
    else
    {
        return [_recipes count];
    }
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{

    NSString *simpleTableIdentifier = @"RecipeCell";

    UITableViewCell *cell = [self.tableView dequeueReusableCellWithIdentifier:simpleTableIdentifier];

    if (cell == nil)
    {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:simpleTableIdentifier];
    }


    if(self.tableView == self.searchDisplayController.searchResultsTableView)
        {
            cell.textLabel.text = _searchResults[indexPath.row];
        }
        else
        {
            cell.textLabel.text = _recipes[indexPath.row];
        }


    return cell;

}

// Delegate Protocol


- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    NSLog(@"row %i and section %i",indexPath.row,indexPath.section);
    _recipeName = _recipes[indexPath.row];

    [self performSegueWithIdentifier:@"CellSelectionSegue" sender:self];


}

# pragma mark Segue method

-(void) prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
    NSLog(@"segue");

    detailViewController *detailVC = segue.destinationViewController;
    detailVC.string = _recipeName;
    NSLog(@"%@",_recipeName);


}

# pragma mark Searchbar datasource

- (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope
{
    NSPredicate *resultPredicate = [NSPredicate
                                    predicateWithFormat:@"SELF contains[cd] %@",
                                    searchText];

    _searchResults = (NSArray *)[_recipes filteredArrayUsingPredicate:resultPredicate];

    NSLog(@"%@",_searchResults);
}

-(BOOL)searchDisplayController:(UISearchDisplayController *)controller
shouldReloadTableForSearchString:(NSString *)searchString
{
    [self filterContentForSearchText:searchString
                               scope:[[self.searchDisplayController.searchBar scopeButtonTitles]
                                      objectAtIndex:[self.searchDisplayController.searchBar
                                                     selectedScopeButtonIndex]]];

    return YES;
}

@end

Answer 1

您是否为 SearchDisplayController 设置了委托(delegate)？

self.searchDisplayController.searchResultsDelegate = self;
self.searchDisplayController.searchResultsDataSource = self;
self.searchDisplayController.delegate = self;

编辑:

我会在这里编辑我的评论。我相信引用

if (self.tableView == self.searchDisplayController.searchResultsTableView)

应该是

if (tableView == self.searchDisplayController.searchResultsTableView)

原因是 self.tableView 永远不会是 SearchDisplayController 因为当启动搜索时它实际上创建了一个新的 UITableViewController原创。