ios - 用换行符替换多个空格，但保留单个空格

Question

我正在尝试操作一个 NSString。我想整理输出。如果一行中有多个空格，则应将其替换为换行符。

NSString *myString = @"Name: Tom Smith           Old address       street name : 31 Fox Road      Dixton       0000";

我想要的 NSLog() 输出:

Name: Tom Smith                  Old address     street name : 31 Fox Road                  Dixton         0000

Here's a bit of logic I have been working on. I'm not sure if it's correct.

    if (word_spacing > 1)
        insert word in new line "\n"
    else
        carry on from the same line

Answer 1

您可以使用 NSCharacterSet 和 componentsSeparatedByString 来完成。

解决方案:

// Your string
NSString *myString = @"Name: Tom Smith           Old address       street name : 31 Fox Road      Dixton       0000";

// Seperating words which have more than 1 space with another word
NSArray *components    = [myString componentsSeparatedByString:@"  "];
NSString *newString    = @"";
NSString *oldString    = @"";
for (NSString *tempString in components)
{
    // Creating new string
    newString = [oldString stringByAppendingString:[tempString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]]];

    // Avoiding new line characters or extra spaces contained in the array
    if (![oldString isEqualToString:newString])
    {
        newString = [newString stringByAppendingString:@"\n"];
        oldString = newString;
    }
}
NSLog(@"%@",newString);

或

你可以使用NSRegularExpression

NSString *pattern = [NSString stringWithFormat:@"  {2,%d}",[myString length]];

NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:NSRegularExpressionCaseInsensitive error:&error];

NSString *output = [regex stringByReplacingMatchesInString:myString options:0 range:NSMakeRange(0, [myString length]) withTemplate:@"\n"];
NSLog(@"%@", output);