ios - 识别然后加载/重新加载特定的 tableView

Question

我在 Storyboard上设置了一个 View Controller ，并在该 View Controller 中插入了一个 tableView。我想做一个 [self.tableView reloadData]。

这就是我的 viewController.m 的样子。我的 tableView 是一个名为 sharedView 的 IBOutlet，因此在方法中有名称，但是当我调用 configureView 时我在 viewDidLoad 上做错了，随后 [self.sharedView reloadData]; 数据没有出现在表格内。

    #import "DetailViewController.h"
    #import "sharedUsersTable.h"

    @interface DetailViewController ()
    - (void)configureView;
    @end

    @implementation DetailViewController

    #pragma mark - Managing the detail item

    - (void)setDetailItem:(id)newDetailItem
    {
        if (_detailItem != newDetailItem) {
            _detailItem = newDetailItem;

            // Update the view.
            [self configureView];
        }
    }

    - (void)configureView
    {
        // Update the user interface for the detail item.

        if (self.detailItem) {
            self.detailDescriptionLabel.text = [[self.detailItem objectForKey:@"lock_name"] description];

            activeUsers = [self.detailItem objectForKey:@"active_shared_users"];
            [self.sharedView reloadData];

            //NSLog(@"Info: %@", activeUsers);
        }
    }


    - (void)viewDidLoad
    {
        [super viewDidLoad];
        // Do any additional setup after loading the view, typically from a nib.
        [self configureView];
    }

    - (void)didReceiveMemoryWarning
    {
        [super didReceiveMemoryWarning];
        // Dispose of any resources that can be recreated.
    }

    - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
    {
        return 1;
    }

    -(NSString *)sharedView:(UITableView *)sharedView titleForHeaderInSection:(NSInteger)section {
        return @"Shared with";
    }

    - (NSInteger)sharedView:(UITableView *)sharedView numberOfRowsInSection:(NSInteger)section
    {
        return activeUsers.count;
    }

    - (sharedUsersTable *)sharedView:(UITableView *)sharedView cellForRowAtIndexPath:(NSIndexPath *)indexPath
    {
        static NSString *CellIdentifier = @"sharedUser";


        sharedUsersTable *cell = [sharedView dequeueReusableCellWithIdentifier:CellIdentifier];
        if (cell == nil) {
            cell = [[sharedUsersTable alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
        }

        NSDictionary *key;
        NSString *name;
        NSString *email;
    //    NSString *permission;

        key = [activeUsers objectAtIndex:indexPath.row];
        name = [key objectForKey:@"shared_user_name"];
        email = [key objectForKey:@"email"];

        NSLog(@"Info: %@", name);

        cell.textLabel.text = [NSString stringWithFormat:@"%@", name];
        cell.detailTextLabel.text = [NSString stringWithFormat:@"%@", email];

        return cell;
    }

    - (BOOL)tableView:(UITableView *)tableView canEditRowAtIndexPath:(NSIndexPath *)indexPath
    {
        // Return NO if you do not want the specified item to be editable.
        return YES;
    }


    @end

Answer 1

您应该添加有关您的 VC 正在实现的协议(protocol)的信息:

@interface DetailViewController () <UITableViewDataSource, UITableViewDelegate>
- (void)configureView;
@end

然后:

- (void)configureView
    {
        // Update the user interface for the detail item.

        if (self.detailItem) {
            self.detailDescriptionLabel.text = [[self.detailItem objectForKey:@"lock_name"] description];

            activeUsers = [self.detailItem objectForKey:@"active_shared_users"];
            /* I assume that Your table view is self.sharedView though You should change the name and I assume that it is connected to VC */
            self.sharedView.dataSource = self; 
            self.sharedView.delegate = self; 

            [self.sharedView reloadData];

            //NSLog(@"Info: %@", activeUsers);
        }
    }

您还可以直接在 Storyboard 中设置数据源和委托(delegate) - 我认为您必须按住 ctrl 并从 TableView 拖动到 vc。抱歉，如果这不正确 - 我已经有一段时间不使用 IB 了 - 只有代码。

还有一件事——读这个: https://developer.apple.com/library/ios/documentation/UIKit/Reference/UITableViewDataSource_Protocol/Reference/Reference.html#//apple_ref/occ/intf/UITableViewDataSource并将方法名称更改为与协议(protocol)中的名称完全相同 - 如果您不这样做，它将无法工作。

为了更好地理解数据源和委托(delegate)，请尝试: https://developer.apple.com/library/ios/documentation/userexperience/conceptual/tableview_iphone/CreateConfigureTableView/CreateConfigureTableView.html