python - 计算数字总和的调试函数

Question

我刚刚开始调试。任务是查找和调整 2 个函数的错误代码:一个计算奇数位的和，而另一个计算偶数位。

我已经找到问题所在，但不知道之后该怎么办。

def sum_odd_digits(number):
dsum = 0
# only count odd digits
while number % 2 != 0:
    # add the last digit to the sum
    digit = number % 10
    dsum = dsum + digit
    # divide by 10 (rounded down) to remove the last digit
    number = number // 10
return dsum

def sum_even_digits(number):
m = 1 # the position of the next digit
dsum = 0 # the sum
while number % (10 ** m) != 0:
    # get the m:th digit
    digit = (number % (10 ** m)) // (10 ** (m - 1))
    # only add it if even:
    if digit % 2 == 0:
        dsum = dsum + digit
    m = m + 1
return dsum

对于 sum_odd_digits 函数，如果奇数位在偶数位之前，它会给出错误的值(例如 129 只返回 9，而不是 10)。对于 sum_even_digits 函数，存在无限循环，我不知道如何解决这个问题。

Answer 1

def sum_odd_digits(number):
    dsum = 0

    while number > 0:
        # add the last digit to the sum if it is odd
        digit = number % 10
        if digit%2!=0: # implies odd digit
            dsum = dsum + digit
        # divide by 10 (rounded down) to remove the last digit
        number = number // 10
    return dsum

def sum_even_digits(number):
    dsum = 0

    while number > 0:
        # add the last digit to the sum if it is even
        digit = number % 10
        if digit%2==0:  # implies even digit
            dsum = dsum + digit
        # divide by 10 (rounded down) to remove the last digit
        number = number // 10
    return dsum