ios - 'NSDictionary' 方法 'dictionaryWithObjectsAndKeys:' 的参数应该是 Objective-C 指针类型，而不是 int

Question

-(NSMutableArray*)getLSBGoalList
{
    int userId = [[[AppManager sharedAppManager].userInfo objectForKey:USER_ID] intValue];

    NSString *query = [NSString stringWithFormat:@"SELECT * FROM tblLBGoal WHERE userId = %d ORDER BY groupId", userId];

    FMResultSet *rs = [database executeQuery:query];
    NSMutableArray *arrLSBGoals = [NSMutableArray array];
    while([rs next])
    {
        NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:
                              [NSNumber numberWithInt:[rs intForColumn:@"lbGoalId"]], @"lbGoalId",
                              [NSNumber numberWithInt:[rs intForColumn:@"groupId"]], @"groupId",
                              [NSNumber numberWithInt:[rs intForColumn:@"userId"]], @"userId",
                              [rs stringForColumn:@"uuid"],@"uuid",
                              [NSNumber numberWithInt:[rs intForColumn:@"dataSyncType"]], @"dataSyncType",
                              [NSNumber numberWithInt:[rs intForColumn:@"idealValue"]], @"idealValue",
                              [NSNumber numberWithInt:[rs intForColumn:@"targetValue"]], @"targetValue",nil,
                              [NSNumber numberWithInt:[rs intForColumn:@"isTargetSet"]], @"isTargetSet",nil];

        [arrLSBGoals addObject:dict];
    }
    return arrLSBGoals;
}

我正在使用上面的代码，当我分析我的项目时，我收到一条警告，“NSDictionary”方法“dictionaryWithObjectsAndKeys:”的参数应该是一个 objective-C 指针类型，而不是 int。 Analyzer 向我展示了以下修复方法，但我不明白该怎么做。谁能帮帮我。

Answer 1

你在最后一行中有一个额外的nil:

[NSNumber numberWithInt:[rs intForColumn:@"targetValue"]], @"targetValue",nil,  // here
[NSNumber numberWithInt:[rs intForColumn:@"isTargetSet"]], @"isTargetSet",nil];

使用较新的 Objective-C 字典字面量语法更易于阅读，并且不需要终止 nil:

NSDictionary *dict = @{
   @"lbGoalId" : @([rs intForColumn:@"lbGoalId"]),
   @"groupId" : @([rs intForColumn:@"groupId"]),
   // etc.
};