ios - 使用 Cordova/Phonegap 通过 Filetransfer 发送录制的文件

Question

我正在尝试发送通过媒体插件录制的录音。

当我尝试发送文件时出现 FileError.NOT_FOUND_ERR 错误:

Error opening file /myRecording100.wav: Error Domain=NSCocoaErrorDomain Code=260 "The operation couldn’t be completed. (Cocoa error 260.)" UserInfo=0xa358640 {NSFilePath=/myRecording100.wav, NSUnderlyingError=0xa34fb30 "The operation couldn’t be completed. No such file or directory"}
2014-08-06 17:02:26.919 Bring Me[40961:c07] FileTransferError {
    code = 1;
    source = "/myRecording100.wav";
    target = "http://XXXX.xom";
}

但是，录音后我可以播放录音。

为什么我可以播放文件(显示文件已录制并正确保存)但 FileTransfer 无法发送？

这是我的代码(适用于 ios):

var my_recorder = null;
var mediaFileFullName = null; // iOS
var mediaRecFile = "myRecording100.wav";
var checkFileOnly = false;

/******
 Call when start recording
******/
function startRecording() {
    checkFileOnly = false;
    window.requestFileSystem(LocalFileSystem.PERSISTENT, 0, onSuccessFileSystem, function() {
        console.log("***test: failed in creating media file in requestFileSystem");
    });
}

function onSuccessFileSystem(fileSystem) {
    if (checkFileOnly === true) {        
        // Get File and send
        fileSystem.root.getFile(mediaRecFile, { create: false, exclusive: false }, onOK_GetFile, onFail_GetFile);
    }
    else {
        // Create File
        fileSystem.root.getFile(mediaRecFile, { create: true, exclusive: false }, onOK_SaveFile, onFail_GetFile);
      }
}

/* Save the file*/
function onOK_SaveFile(fileEntry) {
    mediaFileFullName = fileEntry.fullPath;
    my_recorder = new Media(mediaFileFullName, 
        function() { document.location ="address_form.html"; // Redirect the user to an other page  },
        function(err) { console.log("playAudio():callback Record Error: "+err);}
    );
    my_recorder.startRecord();
}

/* Get the file and send it */
function onOK_GetFile(fileEntry) {
    mediaFileFullName = fileEntry.fullPath;
    /*
        // Read the recorded file is WORKING !
        my_player = new Media(mediaFileFullName, onMediaCallSuccess, onMediaCallError);
        my_player.play();
    */
    var options = new FileUploadOptions();
    options.fileKey = "want";
    options.fileName = "file.wav";
    options.mimeType = "audio/wav";
    options.chunkedMode = false;
    options.params = parameters;

    var ft = new FileTransfer();
    ft.upload(mediaFileFullName, "https://SERVER_ADDRESS", win, fail, options);
}



/******
    Called when stop recording
******/
function stopRecording() {
    if (my_recorder) {
        my_recorder.stopRecord();
    }
}

Answer 1

从 File 插件 v1.0 开始，要通过 file-transfer 插件上传文件系统中的文件，您需要使用 .toURL() 方法来访问它。

If you are upgrading to a new (1.0.0 or newer) version of File, and you have previously been using entry.fullPath as arguments to download() or upload(), then you will need to change your code to use filesystem URLs instead.

FileEntry.toURL() and DirectoryEntry.toURL() return a filesystem URL of the form

所以正确的代码是:

/* Get the file and send it */
function onOK_GetFile(fileEntry) {

    var options = new FileUploadOptions();
    options.fileKey = "want";
    options.fileName = "file.wav";
    options.mimeType = "audio/wav";
    options.chunkedMode = false;
    options.params = parameters;

    var ft = new FileTransfer();
    ft.upload(fileEntry.toURL(), "https://SERVER_ADDRESS", win, fail, options);
}