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eclipse - HTTP 状态 [404] ？ [Not Found](源站没有找到当前表示)

转载 作者：行者123 更新时间：2023-11-28 21:56:11 25 4
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我使用(jsp、servlet、apache tomcat 9、eclipse neon、oracle 11g)创建了一个 servlet 项目。我已经创建了 index.jsp(获取登录详细信息并重定向到 LoginServlet 以在数据库表中验证用户名和密码。在 index.jsp 中，我什至提到了一个“register.jsp”链接，用于在第一次使用时进行注册)。当我运行项目 index.jsp 页面时打开。

当我提供用户 ID 和密码详细信息(在数据库中手动输入用户名和密码详细信息)时，它成功地重定向了 LoginServlet，然后在 servlet 上进行了重定向。

但是当我点击“注册”链接时，出现上述错误 (HTTP Status [404] ? [Not Found] Type Status Report Message/TodayServlet/register.jsp Description The origin server did找不到目标资源的当前表示形式，或者不愿意透露存在的表示形式。Apache Tomcat/9.0.0.M20)

我的问题来自 index.jsp，我无法打开“register.jsp”(“register.jsp provided through anchor tag in index.jsp”)。

目录结构和主要jsp和servlets以及web.xml代码请找到我的附件。

index.jsp(主要代码):

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<center>
<form action="LoginServlet" method="post">
enter name:<input type="text" name="name"><br>
enter pass:<input type="password" name="pass"><br>

<a href="register.jsp">New User Register here...!!!</a><br>
<input type="submit" value="login"><br>
</form>
</center>
</body>
</html>

register.jsp(主要代码):

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<center>
<form action="RegisterServlet" method="post">
enter name:<input type="text" name= "name1"> <br>
enter pass:<input type="text" name= "pass1"><br>
enter email:<input type="text" name="email1"><br>
<input type="submit" value="register"><br>
</form>
</center>
</body>
</html>

RegisterServlet.java(主要代码):

package com.pack;

import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;


public class RegisterServlet extends HttpServlet {

    protected void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
        res.setContentType("text/html");
        PrintWriter out=res.getWriter();
        String uname1=req.getParameter("name1");
        String upass1=req.getParameter("pass1");
        String uemail1=req.getParameter("email1");
        req.setAttribute("username", uname1);
        try{
        Connection conn=DbConnection.getConnection();
        PreparedStatement ps=conn.prepareStatement("insert into register_table values(?,?,?)");
        ps.setString(1, uname1);
        ps.setString(2, upass1);
        ps.setString(3, uemail1);
        int i=ps.executeUpdate();
        if(i>0){
            req.getRequestDispatcher("WelcomeServlet").forward(req, res);
        }
        else{
            out.print("try registering again ");
            req.getRequestDispatcher("register.jsp").include(req, res);
        }
        }
            catch(Exception e){
            e.printStackTrace();
        }
    }

}

我在使用其他 servlet(LoginServlet、WelcomeServlet...)时没有遇到任何问题

LoginServlet.java(完整代码):

package com.pack;

import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;

import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class LoginServlet extends HttpServlet {

    protected void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
    RequestDispatcher rd= null;
        res.setContentType("text/html");
    PrintWriter out=res.getWriter();
    String upassword=req.getParameter("pass");
    out.println(upassword);

    String uname2=req.getParameter("name");
    out.println(uname2);
    try{
        Connection con=DbConnection.getConnection();
        out.println("conection established");
        PreparedStatement ps=con.prepareStatement("select * from register_table where username=? and password=?");
        ps.setString(1, uname2);
        ps.setString(2, upassword);
        ResultSet rs= ps.executeQuery();

        if(rs.next()){
            out.println("username is "+rs.getString(1)+" and pwd is "+rs.getString(2));
            req.setAttribute("uid", uname2);
            req.getRequestDispatcher("MainServlet").forward(req, res);
        }else{
            out.println("user name or password incorrect.Check and login again or register");
            req.getRequestDispatcher("index.jsp").include(req, res);
        }
    }catch(Exception e){
        e.printStackTrace();
    }

    }

}

web.xml(代码):

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>TodayServlet</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <description></description>
    <display-name>LoginServlet</display-name>
    <servlet-name>LoginServlet</servlet-name>
    <servlet-class>com.pack.LoginServlet</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>LoginServlet</servlet-name>
    <url-pattern>/LoginServlet</url-pattern>
  </servlet-mapping>
  <servlet>
    <description></description>
    <display-name>RegisterServlet</display-name>
    <servlet-name>RegisterServlet</servlet-name>
    <servlet-class>com.pack.RegisterServlet</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>RegisterServlet</servlet-name>
    <url-pattern>/RegisterServlet</url-pattern>
  </servlet-mapping>
  <servlet>
    <description></description>
    <display-name>WelcomeServlet</display-name>
    <servlet-name>WelcomeServlet</servlet-name>
    <servlet-class>com.pack.WelcomeServlet</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>WelcomeServlet</servlet-name>
    <url-pattern>/WelcomeServlet</url-pattern>
  </servlet-mapping>
  <servlet>
    <description></description>
    <display-name>MainServlet</display-name>
    <servlet-name>MainServlet</servlet-name>
    <servlet-class>com.pack.MainServlet</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>MainServlet</servlet-name>
    <url-pattern>/MainServlet</url-pattern>
  </servlet-mapping>

</web-app>

目录结构:

  1. TodayServlet(项目名)>src>com.pack>servlets
  2. web-inf>(web.xml 和 jsp 文件)

directory structure

最佳答案

这个问题我纠结过很多次。

我目前使用的解决方案是webapp(或者你保存 View 如jsp的文件夹)是否在部署程序集下。

试试这个:

右键点击项目 > Build Path > Configure Build path > Deployment Assembly > Add(right hand side) > Folder > (添加你的jsp文件夹，默认是src/主/网络应用)

关于eclipse - HTTP 状态 [404] ？ [Not Found](源站没有找到当前表示)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/44450206/

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