ios - 工作日本地通知未触发

Question

我正在构建一个允许用户在每个工作日重复本地通知的应用程序，因为苹果没有 WeekDays 的重复间隔我需要为每个工作日创建一个本地通知。我做了一个 for 循环，循环次数是工作周天数的 5 倍。不过好像没开火。但是当我删除通知时，我看到了所有五个，只是不会开火。这就是我的代码的样子。

NSDate *today = [NSDate date];
UILocalNotification* localNotification = [[UILocalNotification alloc] init];
localNotification.fireDate = _alarmTime;
localNotification.alertBody = @"Wake up or pay-up!";
localNotification.timeZone = [NSTimeZone systemTimeZone];
localNotification.alertAction = @"Wake up or pay-up!";
localNotification.soundName = @"sound_ring.caf";

NSCalendar *gregCalendar = [[NSCalendar alloc]initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *dateComponent = [gregCalendar components:NSYearCalendarUnit  | NSWeekCalendarUnit fromDate:_alarmTime];

switch (_repeatInt) {
    case 1:
        localNotification.repeatInterval = NSCalendarUnitDay;
        [[UIApplication sharedApplication] scheduleLocalNotification:localNotification];
        _repeatString = @"Everyday";
        break;

    case 2:
        //Attempting to create 5 local notifications with different days but same time.
        for (int i = 2; i <= 6; i++){

            [dateComponent setWeekday:i]; // 2 = mon // 3= tues // 4 = wends // 5 = thurs // 6 = fri
            NSDate *fireDate = [gregCalendar dateFromComponents:dateComponent];

            UILocalNotification *localNotification2 = [localNotification copy];
            localNotification2.fireDate = fireDate;
            localNotification2.repeatInterval = NSWeekCalendarUnit;
            [[UIApplication sharedApplication] scheduleLocalNotification:localNotification2];
            NSLog(@"%D",i);

        }

如果有人有任何想法，请告诉我!提前致谢。

更新:

NSDate *startDate = [gregCalendar dateFromComponents:dateComponent];
            [dateComponent setMonth:0];
            [dateComponent setDay:i]; // 2 = mon // 3= tues // 4 = wends // 5 = thurs // 6 = fri
            [dateComponent setYear:0];

            NSDate *fireDate = [gregCalendar dateByAddingComponents:dateComponent toDate:startDate options:0];

            UILocalNotification *localNotification2 = [localNotification copy];
            localNotification2.fireDate = fireDate;
            localNotification2.repeatInterval = NSCalendarUnitWeekOfYear;
            [[UIApplication sharedApplication] scheduleLocalNotification:localNotification2];
            NSLog(@"%D",i);

Answer 1

好吧，我终于能够让本地通知在每个工作日重复，我添加了 [setHour] 和 [setMinute] 并更改了 for 循环中的 int到 NSUInteger。下面是我的代码。

NSCalendar *gregCalendar = [[NSCalendar alloc]initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *dateComponent = [gregCalendar components:NSYearCalendarUnit  | NSWeekCalendarUnit fromDate:_alarmTime];

switch (_repeatInt) {
    case 1:
        localNotification.repeatInterval = NSCalendarUnitDay;
        [[UIApplication sharedApplication] scheduleLocalNotification:localNotification];
        _repeatString = @"Everyday";
        break;

    case 2:

        for (NSUInteger i = 2; i <= 6; i++) {

            NSDateComponents *components = [gregCalendar components:(NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:_alarmTime];
            NSInteger hour = [components hour];
            NSInteger minute = [components minute];

            [dateComponent setMinute:minute];
            [dateComponent setWeekday:i]; // 2 = mon // 3= tues // 4 = wends // 5 = thurs // 6 = fri
            [dateComponent setHour:hour];

            NSDate *fireDate = [gregCalendar dateFromComponents:dateComponent];

            UILocalNotification *localNotification2 = [[UILocalNotification alloc] init];
            localNotification2.fireDate = fireDate;
            localNotification2.alertBody = @"Wake up or pay-up!";
            localNotification2.timeZone = [NSTimeZone systemTimeZone];
            localNotification2.alertAction = @"Wake up or pay-up!";
            localNotification2.soundName = @"sound_ring.caf";
            localNotification2.repeatInterval = NSCalendarUnitWeekOfYear;
            [[UIApplication sharedApplication] scheduleLocalNotification:localNotification2];
            NSLog(@"%lu",(unsigned long)i);

        }