python - 如何在模板中引用函数的结果？ Django

Question

我有这些模型:

# this is model for user
class UserProfile(models.Model):
    user = models.OneToOneField(User, related_name='profile')

    profilepic = models.ImageField(blank=True)


    city = models.ForeignKey(City)
    slug = models.SlugField(unique=True)


    def save(self, *args, **kwargs):
        self.slug = slugify(self.user.username)
        super(UserProfile, self).save(*args, **kwargs)

    def __unicode__(self):
        return self.user.username

    @property
    def avg_rating(User):
        return UserProfile.userrating_set.all().aggregate(Avg('rating'))['rating__avg']


# this is the model for user ratings - one to many relationship with User
class UserRating(models.Model):
    user = models.ForeignKey(User)
    comment = models.CharField(max_length=500)
    for_username = models.CharField(max_length=128)
    rating = models.IntegerField(default=5)

    def __unicode__(self):
        return unicode(self.rating)

我想在我的模板中引用属性 (avg_rating) 的结果，这样我就可以显示每个用户的评分。我试过了它显示空白结果:

{% for user in users %}
{{ user.profile.avg_rating }}

此外，这是被调用的 View :

def index(request):
    user_list = User.objects.select_related().order_by('-userrating')[:5]

    city_list = City.objects.order_by('-name')[:5]

    context_dict = {"users": user_list, "cities" : city_list}

    return render(request, "index.html", context_dict)

我目前正在学习 Django，如果这很明显，我深表歉意。

Answer 1

avg_rating 的 User 参数根本没有使用。尝试将其重写为:

def avg_rating(self):
    return self.user.userrating_set.all().aggregate(Avg('rating'))['rating__avg']

您还可以删除 @property 装饰器，因为您还可以使用相同语法(即不使用 ())在 Django 模板中使用方法，例如:

{{ user.profile.avg_rating }}