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python - Matplotlib 中的 3D 参数化曲线不遵循 zorder。解决方法?

转载 作者:行者123 更新时间:2023-11-28 21:46:39 29 4
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我正在使用 Matplotlib 设计三维插图。一切都很好,除了(红色)参数曲线得到错误的 zorder 而(绿色)参数曲面完全正确绘制。

由以下代码生成的输出: Output generated by code below

我知道 Matplotlib 在精确计算对象的 zorder 方面的能力有限,但由于它可以为参数化表面做到这一点,所以它似乎是 Matplotlib 中的一个错误。

就是说,是否有任何方法可以强制执行正确的 z 顺序以使事情快速进行?似乎我只能说,正确的透明蓝色平面位于其他一切之上。但是,将 zorder 参数放入 PolyCollection 似乎没有任何效果,将显式 zorder 参数放入绘制读取线的 plot 函数将弄乱其相对于绿色表面的顺序。

有没有办法强制将正确的蓝色透明表面置于所有内容之上?这是我到目前为止的代码:

#!/bin/env python3

from pylab import *
from mpl_toolkits.mplot3d import *

from matplotlib.collections import PolyCollection
from matplotlib.colors import colorConverter
from matplotlib.patches import FancyArrowPatch

rc('text', usetex=True)
rc('font', size=20)

fig = figure(figsize=(11,6))
ax = fig.gca(projection='3d')

ax.set_axis_off()

def f(x,t):
return t/2 * 0.55*(sin(2*x)+0.4*x**2-0.65)

c_plane = colorConverter.to_rgba('b', alpha=0.15)

N = 50
y = linspace(-1,1,N)
t = linspace(0,2,N)
yy, tt = meshgrid(y, t)
zz = f(yy,tt)

ax.plot(0*ones(y.shape), y, f(y,0), '-g', linewidth=3)
ax.plot(2*ones(y.shape), y, f(y,2), '-g', linewidth=3)

yt = 0.7*y
zt = f(yt, t) + 0.2*t

ax.plot(t, yt, zt, '-r', linewidth=3)
ax.plot((0,2), (yt[0], yt[-1]), (zt[0], zt[-1]), 'or')

ax.plot([2,2,2], [-1,yt[-1],yt[-1]], [zt[-1],zt[-1],-1], 'k--')
ax.plot(2*ones(y.shape), yt, f(yt,2)+0.1*(y+1), 'g:', linewidth=2)
ax.plot((2,2),
(yt[0], yt[-1]),
(f(yt[0], 2), f(yt[-1], 2) + 0.1*(y[-1]+1)), 'og')
ax.plot((0,2,2),
(-1,-1,zt[-1]),
(0,yt[-1],-1), 'ok')

ax.text(0, -1.1, 0, r'$p(0)=0$', ha='right', va='center')
ax.text(2, -1.05, zt[-1], r'$p(T)$', ha='right', va='center')
ax.text(0, -1.0, 1, r'$p$', ha='right', va='bottom')
ax.text(0, 1, -1.1, r'$q$', ha='center', va='top')
ax.text(0, -1, -1.1, r'$t=0$', ha='right', va='top')
ax.text(2, -1, -1.1, r'$t=T$', ha='right', va='top')
ax.text(2, yt[-1]-0.05, -1.05, r'$q(T)=q^*$', ha='left', va='top')
ax.text(0, 0.5, 0.05, r'$\mathcal{M}(0)$', ha='center', va='bottom')
ax.text(2, 0.1, -0.8, r'$\mathcal{M}(T)$', ha='center', va='bottom')

arrowprops = dict(mutation_scale=20,
linewidth=2,
arrowstyle='-|>',
color='k')

# For arrows, see
# https://stackoverflow.com/questions/29188612/arrows-in-matplotlib-using-mplot3d
class Arrow3D(FancyArrowPatch):
def __init__(self, xs, ys, zs, *args, **kwargs):
FancyArrowPatch.__init__(self, (0,0), (0,0), *args, **kwargs)
self._verts3d = xs, ys, zs

def draw(self, renderer):
xs3d, ys3d, zs3d = self._verts3d
xs, ys, zs = proj3d.proj_transform(xs3d, ys3d, zs3d, renderer.M)
self.set_positions((xs[0],ys[0]),(xs[1],ys[1]))
FancyArrowPatch.draw(self, renderer)

a = Arrow3D([0,2], [-1,-1], [-1,-1], **arrowprops)
ax.add_artist(a)
a = Arrow3D([0,0], [-1,-1], [-1,1], **arrowprops)
ax.add_artist(a)
a = Arrow3D([0,0], [-1,1], [-1,-1], **arrowprops)
ax.add_artist(a)

# For surface illumination, see
# http://physicalmodelingwithpython.blogspot.de/2015/08/illuminating-surface-plots.html

# Get lighting object for shading surface plots.
from matplotlib.colors import LightSource

# Get colormaps to use with lighting object.
from matplotlib import cm

# Create an instance of a LightSource and use it to illuminate the surface.
light = LightSource(70, -120)
white = np.ones((zz.shape[0], zz.shape[1], 3))
illuminated_surface = light.shade_rgb(white*(0,1,0), zz)

ax.plot_surface(tt, yy, zz,
cstride=1, rstride=1,
alpha=0.3, facecolors=illuminated_surface,
linewidth=0)

verts = [array([(-1,-1), (-1,1), (1,1), (1,-1), (-1,-1)])]

poly = PolyCollection(verts, facecolors=c_plane)
ax.add_collection3d(poly, zs=[0], zdir='x')
poly = PolyCollection(verts, facecolors=c_plane)
ax.add_collection3d(poly, zs=[2], zdir='x')

ax.set_xlim3d(0, 2)
ax.view_init(elev=18, azim=-54)

show()

最佳答案

在 Matplotlib 3.5.0 中添加了使用 axis3d 更改绘图顺序的方法。 将参数 'computed_zorder' 设置为 False 允许手动控制绘图顺序

ax = plt.axes(projection='3d',computed_zorder=False)
ax.plot_surface(X1, Y1, Z1,zorder=4.4)
ax.plot_surface(X2, Y2, Z2,zorder=4.5)

较高的“zorders”绘制在顶部。一些常见的艺术家 z 顺序(这样你就不会在你的图例上绘制):

<表类="s-表"><头>艺术家Z 顺序<正文>图像(AxesImage、FigureImage、BboxImage)0补丁,补丁集合1Line2D、LineCollection(包括小刻度、网格线)2主要刻度2.01文本(包括轴标签和标题)3传说5

来自: https://matplotlib.org/stable/gallery/misc/zorder_demo.html

来源:https://github.com/matplotlib/matplotlib/commit/2db6a0429af47102456366f8d3a4df24352b252e(来自:https://github.com/matplotlib/matplotlib/pull/14508)

关于python - Matplotlib 中的 3D 参数化曲线不遵循 zorder。解决方法?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37611023/

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