python - 根据字母的对称性创建镜像词

Question

我创建了这个程序，如果它是对称的，它应该显示一个单词的镜像。不幸的是，当我测试“TIMOTHY”时，它显示它不能被镜像，我不明白为什么这不起作用。

#Program for creating a mirrored
#image word#
def main():

    mirrors = ["A","H","I","M","O","T","U","V","W","X","Y"
               "b","d","i","l","m","o","p","t","v","w","x"]

    word = input("Enter in the word you'd like mirrored: ")

    for x in word:
        if x not in mirrors:
            y = True
            break

    if y == True:
        print("Sorry your word can not be mirrored")


    wordlist = ''.join(word[i] for i in range(len(word) -1, -1, -1 ))

    print(wordlist)




main()    

Answer 1

mirrors = ["A","H","I","M","O","T","U","V","W","X","Y"
               "b","d","i","l","m","o","p","t","v","w","x"]

问题来了。 “b”跟在“Y”之后，中间没有任何逗号。 Python 一个鲜为人知的怪癖是两个相邻的字符串文字会自动连接起来。因此，“Y”和“b”都不在您的列表中，但“Yb”在。

要解决此问题，请添加逗号。

mirrors = ["A","H","I","M","O","T","U","V","W","X","Y",
               "b","d","i","l","m","o","p","t","v","w","x"]

此外，如果您不想在 if y == True block 。