python - 类型错误 : 'Popen' object is not callable

Question

我正在尝试使用子进程模块的“Popen”方法查询 Windows 服务的状态。但是我得到了

TypeError: 'Popen' 对象不可调用

import subprocess, codecs

def serviceStatus(RadiaService):
    status = []
    cmd = 'sc query ' + RadiaService
    pDetails = subprocess.Popen(cmd, shell = True, stdout = subprocess.PIPE)
    for item in pDetails():
        status.append(item)
    finalStatus = b''.join(status).decode('utf-8')
    print(finalStatus)

if __name__ == '__main__':
    serviceStatus('RCA')

错误跟踪:

Traceback (most recent call last):
  File "C:\Alen\Cumulative RHF\Radia_Cumulative_Patch\cumulativeHotFixproject\lib\win32.py", line 39, in <module>
    serviceStatus('RCA')
  File "C:\Alen\Cumulative RHF\Radia_Cumulative_Patch\cumulativeHotFixproject\lib\win32.py", line 33, in serviceStatus
    for item in pDetails():
TypeError: 'Popen' object is not callable

Answer 1

您似乎希望收集子流程的标准输出。您将不得不使用 pDetails.stdout。下面是一个帮助您入门的示例:

import subprocess
p = subprocess.Popen("ls -la", shell=True, stdout=subprocess.PIPE)
output = b''.join(p.stdout).decode('utf-8')
print(output)

基于此，您的代码应如下所示:

import subprocess, codecs

def serviceStatus(RadiaService):
    cmd = 'sc query ' + RadiaService
    pDetails = subprocess.Popen(cmd, shell = True, stdout = subprocess.PIPE)
    return b''.join(pDetails.stdout).decode('utf-8')

def main():
    print(serviceStatus('RCA'))

if __name__ == '__main__':
    main()

注意:您不必将输出收集到列表中，您可以直接将 iterable 提供给 join。如果你需要一个列表，你仍然不必使用for循环，你可以只写status = list(pDetails.stdout)。