gpt4 book ai didi

ios - 如何根据条件设置初始 View Controller ?

转载 作者:行者123 更新时间:2023-11-28 21:41:10 26 4
gpt4 key购买 nike

根据条件用户是否登录到服务器显示不同的模板。如果用户未登录到应用程序服务器,则需要显示 LoginViewController[UIViewController],否则显示 TabBarViewcontroller[UITabBarViewController]。

因为我是第一次使用 Storyboard。谁能建议我在 Storyboard 中处理这种情况?

最佳答案

我是这样做的。

首先,您创建一个名为 LoginViewController 的东西。它实现了您的登录逻辑。您的根 Controller 是 UITabBarController。

现在在 AppDelegate 中:

- (void) doLogin:(NSDictionary *)dict
{
TransactionsViewController *transactions;
BalancesViewController *balances;
ProfileViewController *profile;
UINavigationController *navi;
UITabBarController *root;

root = (UITabBarController *)self.window.rootViewController;

navi = [root.viewControllers objectAtIndex:0];
transactions = [navi.viewControllers objectAtIndex:0];
transactions.delegate = self;

navi = [root.viewControllers objectAtIndex:1];
balances = [navi.viewControllers objectAtIndex:0];
balances.delegate = self;

navi = [root.viewControllers objectAtIndex:2];
profile = [navi.viewControllers objectAtIndex:0];
profile.delegate = self;

[transactions loadDataFromLogin:dict];
[balances loadDataFromLogin:dict];
[profile loadDataFromLogin:dict];
}

- (void) showLoginView
{
assert(loginController == nil);
assert(activityView == nil);

UITabBarController *tabbar = (UITabBarController *)self.window.rootViewController;
loginController = [tabbar.storyboard instantiateViewControllerWithIdentifier:@"LoginViewController"];
loginController.delegate = self;
[tabbar presentModalViewController:loginController animated:YES];
}

- (void) loginWithLogin:(NSDictionary *)dict relogin:(BOOL)relogin
{
NSString *_login = [dict valueForKey:@"email"];
NSString *_pass = [dict valueForKey:@"pass"];
NetworkOperation *op = [NetworkOperation operationLogin:_login pass:_pass];
[NetworkOperation enqueueOperation:op observer:self];
if (!relogin && !loginController)
[self doLogin:dict];
}

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
session = nil;
loginController = nil;

return YES;
}

- (void)applicationDidBecomeActive:(UIApplication *)application
{
// Restart any tasks that were paused (or not yet started) while the application was inactive. If the application was previously in the background, optionally refresh the user interface.
NSString *login = [[NSUserDefaults standardUserDefaults] stringForKey:@"email"];
NSString *pass = [[NSUserDefaults standardUserDefaults] stringForKey:@"pass"];
NSString *name = [[NSUserDefaults standardUserDefaults] stringForKey:@"name"];
if ((login == nil || login.length == 0) ||
(pass == nil || pass.length == 0) ||
(name == nil || name.length == 0)) {
if (!loginController) {
[self.window makeKeyAndVisible];
[self performSelector:@selector(showLoginView) withObject:nil afterDelay:0.1];
}
} else {
NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:login, @"email",
pass, @"pass", name, @"name", nil];
[self loginWithLogin:dict relogin:(session != nil)];
}
}

因此,您的应用代理会检查您是否存储了您的通行证和登录信息。如果是,那么它使用它们登录并切换到您的 Root View Controller 。在我的例子中,它是一个选项卡,以显示带有余额、交易等的几个选项卡。

如果没有登录和通过,则在 Root View Controller 的顶部显示登录 View Controller 。

@session 是您当前的 session 。正如您在代码中看到的那样,登录正在使用排队操作。

如果您需要更多详细信息,请联系我。

关于ios - 如何根据条件设置初始 View Controller ?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31982258/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com