python子进程一个一个运行

Question

我有一些流程:

subprocess.Popen(['python2.7 script1.py')],shell=True)
subprocess.Popen(['python2.7 script2.py')],shell=True)
subprocess.Popen(['python2.7 script3.py')],shell=True)
subprocess.Popen(['python2.7 script4.py')],shell=True)

我希望每一个都在前一个过程完全完成后开始。我是说

subprocess.Popen(['python2.7 script2.py')],shell=True)

开始于

subprocess.Popen(['python2.7 script1.py')],shell=True)

完全完成，其他人也一样。这是因为以前的脚本有输出，它被下一个脚本使用。谢谢

Answer 1

使用subprocess.call :

Run the command described by args. Wait for command to complete, then return the returncode attribute.

在你的例子中:

subprocess.call(['python2.7 script1.py'],shell=True)
subprocess.call(['python2.7 script2.py'],shell=True)
subprocess.call(['python2.7 script3.py'],shell=True)
subprocess.call(['python2.7 script4.py'],shell=True)