python - 如何从具有子元组的元组创建列表？

Question

我有两个列表 a 和 b。然后我创建所有组合，采用 a 的所有双长度组合加上 b 中的每一个:

import itertools as it

a = [1,2,3,4]
b = [5,6]

for i in it.product(it.combinations(a, 2), b):
    print (i)

# output:
  ((1, 2), 5)
  ((1, 2), 6)
  ((1, 3), 5)
  ...

# expected output:
  [1, 2, 5]
  [1, 2, 6]
  [1, 3, 5]
  ...

元组如何在循环操作阶段转化为列表？

Answer 1

以下理解将起作用:

>>> [[*x, y] for x, y in it.product(it.combinations(a, 2), b)]  # Py3
>>> [list(x) + [y] for x, y in it.product(it.combinations(a, 2), b)]  # all Py versions
[[1, 2, 5],
 [1, 2, 6],
 [1, 3, 5],
 [1, 3, 6],
 [1, 4, 5],
 [1, 4, 6],
 [2, 3, 5],
 [2, 3, 6],
 [2, 4, 5],
 [2, 4, 6],
 [3, 4, 5],
 [3, 4, 6]]