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javascript - 错误:无法在“节点”上执行“appendChild”:参数1不是“节点”类型

转载 作者:行者123 更新时间:2023-11-28 21:37:07 28 4
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我正在尝试将图像拖放到div上。图像没有被拖到div上并给出以下错误

Uncaught TypeError: Failed to execute 'appendChild' on 'Node': parameter 1 is not of type 'Node'.draganddrop.html:20 dropdraganddrop.html:26 ondrop





  <!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title>Creativity Dashboard</title>

<!-- Required CSS -->
<link href="css/movingboxes.css" rel="stylesheet">
<link href="css/compare.css" rel="stylesheet">

<!--[if lt IE 9]>
<link href="css/movingboxes-ie.css" rel="stylesheet" media="screen">
<![endif]-->

<!-- Required script -->
<script src="http://code.jquery.com/jquery-1.8.0.min.js"></script>
<script src="js/jquery.movingboxes.js"></script>

<!-- Demo only -->
<link href="demo/demo.css" rel="stylesheet">
<script src="demo/demo.js"></script>

<script>
function allowDrop(ev) {
ev.preventDefault();
}

function drag(ev) {
ev.dataTransfer.setData("text", ev.target.id);
}

function drop(ev) {
ev.preventDefault();
var data = ev.dataTransfer.getData("text");
ev.target.appendChild(document.getElementById(data));
}
</script>
<style>
/* Overall & panel width defined using css in MovingBoxes version 2.2.2+ */
#slider-one {
width: 1003px;
}

#slider-one>li {
width: 150px;
}
</style>
</head>

<body>
<div class="wrapper">
<!-- Slider #1 -->
<ul id="slider-one">

<li><img id="drag1" src="demo/1.jpg" draggable="true"
ondragstart="drag(event)" alt="picture"></li>

<li><img id="drag2" src="demo/2.jpg" draggable="true"
ondragstart="drag(event)" alt="picture"></li>

<li><img id="drag3" src="demo/3.jpg" draggable="true"
ondragstart="drag(event)" alt="picture"></li>

<li><img id="drag5" src="demo/4.jpg" draggable="true"
ondragstart="drag(event)" alt="picture"></li>

<li><img id="drag6" src="demo/5.jpg" draggable="true"
ondragstart="drag(event)" alt="picture"></li>

<li><img id="drag7" src="demo/6.jpg" draggable="true"
ondragstart="drag(event)" alt="picture" id="astronaut"></li>

<li><img id="drag8" src="demo/7.jpg" draggable="true"
ondragstart="drag(event)" alt="picture"></li>

</ul>
<!-- end Slider #1 -->
<div id="dragAnddrop" ondrop="drop(event)"
ondragover="allowDrop(event)" style="width: 12em; height: 12em">
</div>
</div>

<div>
<div class="left">
<img id="drag" draggable="true" ondragstart="drag(event)"
src="images/startingImage.jpg" style="width: 12em;" alt="picture">

</div>
<div class="middle ">
<img id="image3" src="images/startingImage.jpg" class="image-size"
alt="picture" draggable="true" ondragstart="drag(event)"> <img
src="images/harvest.jpg" class="image-size" alt="picture">
</div>
<div class="right">
<img src="images/startingImage.jpg" style="width: 12em;"
alt="picture">
</div>
</div>
</body>
</html>

最佳答案

这实际上是一个简单的答案。

您的函数返回的是字符串而不是div节点。 appendChild只能附加一个节点。

例如,如果您尝试将字符串追加到Child:

var z = '<p>test satu dua tiga</p>'; // is a string 
document.body.appendChild(z);


上面的代码将永远无法工作。将起作用的是:

var z = document.createElement('p'); // is a node
z.innerHTML = 'test satu dua tiga';
document.body.appendChild(z);

关于javascript - 错误:无法在“节点”上执行“appendChild”:参数1不是“节点”类型,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57302350/

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