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node.js - 无法使用 sinon 和 proxyquire 模拟构造函数

转载 作者:行者123 更新时间:2023-11-28 21:35:46 26 4
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我看过几个类似的问题,但没有一个符合我的问题。我正在尝试模拟我在其他测试中做过的构造函数,但在使用 google-auth-library 的情况下我无法让它工作

代码.js

const {OAuth2Client} = require('google-auth-library');
const keys = require('./oauth2.keys.json');

async function getRedirectUrl() {
const oAuth2Client = new OAuth2Client(
keys.installed.client_id,
keys.installed.client_secret,
keys.installed.redirect_uris[0]
);

const authorizeUrl = oAuth2Client.generateAuthUrl({
access_type: 'offline',
scope: 'https://www.googleapis.com/auth/bigquery',
prompt: 'consent'
});

return authorizeUrl;
}

测试.js

let Code = require('../code.js');

describe('code', function() {
let generateUrlStub, tokenStub, mockClient;

before(async () => {
generateUrlStub = sinon.stub().returns('http://example.com');
tokenStub = sinon.stub().returns({tokens: 'tokens'});

mockClient = sinon.stub().returns({
generateAuthUrl: generateUrlStub,
getToken: tokenStub,
});

Code = proxyquire('../Code.js', {
'google-auth-library': mockClient,
});
});

it('should call generateAuthUrl', async function() {
const output = await Code.getRedirectUrl();
sinon.assert.called(generateUrlStub)
});
});

最佳答案

这是单元测试解决方案:

const { OAuth2Client } = require("google-auth-library");
const keys = {
installed: {
client_id: "1",
client_secret: "client_secret",
redirect_uris: ["http://example.com/callback"]
}
};

async function getRedirectUrl() {
const oAuth2Client = new OAuth2Client(
keys.installed.client_id,
keys.installed.client_secret,
keys.installed.redirect_uris[0]
);

const authorizeUrl = oAuth2Client.generateAuthUrl({
access_type: "offline",
scope: "https://www.googleapis.com/auth/bigquery",
prompt: "consent"
});

return authorizeUrl;
}

module.exports = { getRedirectUrl };

index.spec.js:

const proxyquire = require("proxyquire");
const sinon = require("sinon");
const { expect } = require("chai");

describe("code", function() {
let generateUrlStub, tokenStub, code;
beforeEach(() => {
generateUrlStub = sinon.stub().returns("http://example.com");
tokenStub = sinon.stub().returns({ tokens: "tokens" });

code = proxyquire("./", {
"google-auth-library": {
OAuth2Client: sinon.stub().callsFake(() => {
return {
generateAuthUrl: generateUrlStub,
getToken: tokenStub
};
})
}
});
});
afterEach(() => {
sinon.restore();
});

it("should call generateAuthUrl", async function() {
const output = await code.getRedirectUrl();
expect(output).to.be.eq("http://example.com");
sinon.assert.called(generateUrlStub);
});
});

100% 覆盖率的单元测试结果:

  code
✓ should call generateAuthUrl


1 passing (216ms)

---------------|----------|----------|----------|----------|-------------------|
File | % Stmts | % Branch | % Funcs | % Lines | Uncovered Line #s |
---------------|----------|----------|----------|----------|-------------------|
All files | 100 | 100 | 100 | 100 | |
index.js | 100 | 100 | 100 | 100 | |
index.spec.js | 100 | 100 | 100 | 100 | |
---------------|----------|----------|----------|----------|-------------------|

源代码:https://github.com/mrdulin/mocha-chai-sinon-codelab/tree/master/src/stackoverflow/58955304

关于node.js - 无法使用 sinon 和 proxyquire 模拟构造函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58955304/

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