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Python 列表列表操作

转载 作者:行者123 更新时间:2023-11-28 21:31:07 24 4
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我有一个 Python 问题,可以通过多个嵌套 for 循环来解决,但我想知道是否有更简单的方法来解决这个问题,也许可以通过将列表项添加在一起并删除重复项来解决。

我的列表如下所示:

main_list = [["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="92e7e1f7e0a3d2e6f7e1e6bcf1fdff" rel="noreferrer noopener nofollow">[email protected]</a>", "Administration", "100"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="82f7f1e7f0b0c2f6e7f1f6ace1edef" rel="noreferrer noopener nofollow">[email protected]</a>", "Testing", "30"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="cabfb9afb8f88abeafb9bee4a9a5a7" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "45"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="06737563743446726375722865696b" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "90"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="c8bdbbadbafa88bcadbbbce6aba7a5" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "35"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="91e4e2f4e3a2d1e5f4e2e5bff2fefc" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "400"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="c6b3b5a3b4f586b2a3b5b2e8a5a9ab" rel="noreferrer noopener nofollow">[email protected]</a>", "Administration", "95"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="f782849285c4b783928483d994989a" rel="noreferrer noopener nofollow">[email protected]</a>", "Testing", "200"]]

我需要合并电子邮件地址和类别(前两个列表元素)并将重复的第三个条目添加在一起。

所以[user2,开发]来自:

["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="05707660773745716076712b666a68" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "45"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="84f1f7e1f6b6c4f0e1f7f0aae7ebe9" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "90"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="e297918790d0a296879196cc818d8f" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "35"],

至:

["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="86f3f5e3f4b4c6f2e3f5f2a8e5e9eb" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "170"]

这可以通过列表操作实现吗?

谢谢!

最佳答案

使用collections.defaultdict

例如:

from collections import defaultdict


main_list = [["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="c8bdbbadbaf988bcadbbbce6aba7a5" rel="noreferrer noopener nofollow">[email protected]</a>", "Administration", "100"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="fa8f899f88c8ba8e9f898ed4999597" rel="noreferrer noopener nofollow">[email protected]</a>", "Testing", "30"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="01747264733341756472752f626e6c" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "45"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="76030513044436021305025815191b" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "90"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="b1c4c2d4c383f1c5d4c2c59fd2dedc" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "35"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="70050315024330041503045e131f1d" rel="noreferrer noopener nofollow">[email protected]</a>", "Development", "400"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="67121402155427130214134904080a" rel="noreferrer noopener nofollow">[email protected]</a>", "Administration", "95"],
["<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="b5c0c6d0c786f5c1d0c6c19bd6dad8" rel="noreferrer noopener nofollow">[email protected]</a>", "Testing", "200"]]
result = defaultdict(int)
for k, v, n in main_list:
result[(k, v)] += int(n)
result = [list(k) + [v] for k, v in result.items()]
print(result)

输出:

[['<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="b3c6c0d6c182f3c7d6c0c79dd0dcde" rel="noreferrer noopener nofollow">[email protected]</a>', 'Administration', 100],
['<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="9ce9eff9eeaedce8f9efe8b2fff3f1" rel="noreferrer noopener nofollow">[email protected]</a>', 'Testing', 30],
['<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="02777167703042766771762c616d6f" rel="noreferrer noopener nofollow">[email protected]</a>', 'Development', 170],
['<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="b7c2c4d2c584f7c3d2c4c399d4d8da" rel="noreferrer noopener nofollow">[email protected]</a>', 'Development', 400],
['<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="54212731266714203127207a373b39" rel="noreferrer noopener nofollow">[email protected]</a>', 'Administration', 95],
['<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="ec999f899edfac98899f98c28f8381" rel="noreferrer noopener nofollow">[email protected]</a>', 'Testing', 200]]

关于Python 列表列表操作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58852206/

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