javascript - toMatch 不工作

Question

有谁知道为什么这没有通过？

function correctColorDisplay(message, player_turn, selector) {
  if ((message > 0) && (player_turn != 0)) {
    return $(selector).append("<li>" + message + " " + "color(s) are present but not in the correct position in Round " + player_turn + ".</li>");
  }
}

Jasmine :

describe('#correctColorDisplay', function(){
  it('returns a message to the user displaying if a correct color (not positions) was chosen', function(){
    var message = 2
    var playerTurn = 2
    var selector = $('<li></li>')
    correctColorDisplay(message,playerTurn, selector)
    expect(selector).toMatch("<li>" + message + " " + "color(s) are present but not in the correct position in Round " + playerTurn + ".</li>")
  });
});

我不断收到的错误是这条巨大的消息:预期 { 0 : HTMLNode, length : 1, jquery : '1.11.0', constructor : Function, selector : '', toArray : Function, get : Function, pushStack : Function, each, 等等(持续时间更长)

Answer 1

您正在尝试将新创建的 HTMLNode 与正则表达式(在本例中基本上只是一个字符串)相匹配。

Jasmine 的toMatch 函数是针对正则表达式的。

我对 Jasmine 不是很熟悉，但我猜你正在寻找类似的东西:

describe('#correctColorDisplay', function(){
    it('returns a message to the user displaying if a correct color (not positions) was chosen', function() {
        var message = 2;
        var playerTurn = 2;
        var selector = $('<li></li>');
        selector = correctColorDisplay(message, playerTurn, selector);
        expect(selector).toEqual( $("<li><li>" + message + " " + "color(s) are present but not in the correct position in Round " + playerTurn + ".</li></li>") );
    });
});

如果这不起作用，我建议您查看 jasmine-jquery .