python - 使用python PIL获取图像中显示的数字

Question

我想使用 python 和 PIL 获取此图像中的数字:

我的代码:

#!/usr/bin/env python
#encoding=utf-8

import Image,ImageEnhance,ImageFilter
import Data

DEBUG = False

def d_print(*msg):
    global DEBUG
    if DEBUG:
        for i in msg:
            print(i),
        print
    else:
        pass


def Get_Num(l=[]):
    min1 = []
    min2 = []
    print(l)
    for n in Data.N:
        count1=count2=count3=count4=0
        if (len(l) != len(n)):
            print("Wrong pic %s %s " %(len(l),len(n)))
            exit()
        for i in range(len(l)):
            if (l[i] == 1):
                count1+=1
                if (n[i] == 1):
                    count2+=1
        for i in range(len(l)):
            if (n[i] == 1):
                count3+=1
                if (l[i] == 1):
                    count4+=1
        d_print(count1,count2,count3,count4)

        min1.append(count1-count2)
        min2.append(count3-count4)
    d_print(min1,"\n",min2)
    for i in range(10):
        if (min1[i] <= 2 or min2[i] <= 2):
            if ((abs(min1[i] - min2[i])) < 10):
                return i
    for i in range(10):
        if (min1[i] <= 4 or min2[i] <= 4):
            if (abs(min1[i] - min2[i]) <= 2):
                return i

    for i in range(10):
        flag = False
        if (min1[i] <= 3 or min2[i] <= 3):
            for j in range(10):
                if (j != i and (min1[j] < 5 or min2[j] <5)):
                    flag = True
                else:
                    pass
            if (not flag):
                return i
    for i in range(10):
        if (min1[i] <= 5 or min2[i] <= 5):
            if (abs(min1[i] - min2[i]) <= 10):
                return i
    for i in range(10):
        if (min1[i] <= 10 or min2[i] <= 10):
            if (abs(min1[i] - min2[i]) <= 3):
                return i

#end of function Get_Num

def Pic_Reg(image_name=None):
    im = Image.open(image_name)
    im = im.filter(ImageFilter.MedianFilter())
    enhancer = ImageEnhance.Contrast(im)
    im = enhancer.enhance(5)
    im = im.convert('1')
    im.show()
                    #all by pixel
    s = 6          #start postion of first number
    w = 8          #width of each number
    h = 15          #end postion from top
    t = 2           #start postion of top
    im_new = []
    #split four numbers in the picture
    for i in range(4):
        im1 = im.crop((s+w*i+i*2,t,s+w*(i+1)+i*2,h))
        im_new.append(im1.resize((int(10),int(13)), Image.ANTIALIAS))

    s = ""
    for k in range(4):
        l = []
        im_new[k].show()
        for i in range(13):
            for j in range(10):
                if (im_new[k].getpixel((j,i)) == 255):
                    l.append(0)
                else:
                    l.append(1)
        s+=str(Get_Num(l))
    return s
if __name__ == "__main__":
    print(Pic_Reg("3.jpeg"))

代码可以读取一些数字，但并不完美。我需要更好的数字识别。

Answer 1

PIL 不是您要使用的工具。您要做的是执行图像识别，这是一项典型的[并且相当复杂的] AI 任务。

用于执行此类操作的规范的 free-as-in-freedom 库是 OpenCV ，您可以找到 python 绑定(bind)文档 here .

顺便说一句:验证码使用那种图像的原因恰恰是因为教机器如何识别这些数字是极其困难的……它是 Turing testing 的一种形式。专为区分人类和机器人而设计...