循环中的Python错误

Question

我解决了间距问题，并纠正了其他错误。现在它正在做我想做的事，但我选择了选项 2，它将打印出员工的记录 4 次。如果我输入另一个员工，它只会打印第二个而不是第一个。

class EmployeeClass:
def Employee(name, lastName, age, salary):
    name = name
    lastName = lastName
    age = age
    salary = salary
def displayEmployee(x):
    print("Name: " + name + ", " + lastName)
    print("Age: " + age)
    print("Salary: " + salary)

EmployeeArray = []

Continue = True
print ("Employee Information V2.0")

while Continue == True:
print ("Welcome to Employee Information")
print ("1: Add New Record")
print ("2: List Records")
print ("3: Quit")

choice = input()

if choice == "1":
    name = input ("Enter First Name: ")
    EmployeeArray.append(name)
    if name == "":
        Continue = False
        print ("Goodbye!")
        break
    lastName = input ("Enter Last Name: ")
    EmployeeArray.append(lastName)
    age = input ("Enter Age: ")
    EmployeeArray.append(age)
    salary = input ("Enter Salary: ")
    EmployeeArray.append(salary)
elif choice == "2":
    for Employee in EmployeeArray:
        EmployeeClass.displayEmployee(Employee)
        Continue = False
elif choice == "3":
    print ("Bye!")
    break
else:
    print ("Please choose a valid option")
    print ("\n")

Answer 1

您的错误消息将指示发生此问题的行号。基本上，您混合使用制表符和空格，因此您只需要一致地使用其中一个来进行缩进。

PEP8 - The Style Guide for Python建议使用 spaces 并且还注意到:

When invoking the Python command line interpreter with the -t option, it issues warnings about code that illegally mixes tabs and spaces. When using -tt these warnings become errors. These options are highly recommended!

通过简要检查您的来源，似乎在 print 语句前面有制表符 - 用空格替换它们(这也是它们在上面的帖子中未正确呈现的原因)

while Continue == True:
    print ("Welcome to Employee Information")
    print ("1: Add New Record")
    print ("2: List Records")
    print ("3: Quit")

可能还有其他地方，你得仔细检查。事实上，我怀疑你的代码在你的帖子中没有正确缩进的地方可能值得一看。

为了避免这样的问题，最好使用一个编辑器或 IDE，它会始终为您缩进相同的字符。