python - TypeError : range() integer end argument expected, 在 Python 中得到 str

Question

我是新手，正在尝试使用 Python。我用 python 编写了一个程序，当我执行时出现错误。谁能帮帮我？

程序:

first = raw_input("Enter the first no:")
second = raw_input("Enter Second no:")
if first <= 0:
        print "Enter a valid number"
if second <= first:
        print "Sencond number should be greater than first"
for x in range(first,second):
        for i in range(2, i):
                if x % i == 0:
                        j = x/i
                        print x,  " is not a prime no"
                        print "%d = %d*%d" % (x, i, j)
                        break;
                else:
                        print x, " is not a prime number"

输入和错误:

Enter the first no:1
Enter Second no:9
Traceback (most recent call last):
  File "today1.py", line 7, in <module>
    for x in range(first,second):
TypeError: range() integer end argument expected, got str.

提前谢谢你。

Answer 1

raw_input() 返回一个字符串。

试试这段代码:

    first = int(raw_input("Enter the first no:"))
    second = int(raw_input("Enter Second no:"))

你确定 for i in range(2, i): 不应该是 for i in range(2, x): 吗？