Python 展开列表中的整数并对它们进行排序

Question

我有一个列表:

l = [[120,137],[112,119]]

我想扩展数字并对它们进行排序......预期输出:

newl = [112, 113,....,119,120,121...,137]

感谢您的任何建议...

Answer 1

一种方法是

>>> xx = []
>>> for x in l:
...   a, b = x[0], x[1]
...   xx += range(a, b+1)
... 
>>> xx
[120, 121, 122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137, 112, 113, 114, 115, 116, 117, 118, 119]
>>> sorted(xx)
[112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137]
>>> 

或者只是(基于@wim 的评论):

for a, b in l:
    xx += range(a, b+1)

应该够了