python - 单元测试 get_absolute_url django

Question

我对 Django 和编写测试还很陌生。我目前正在从事一个项目，该项目有两个模型，Project 和 Technologies。项目模型与技术模型具有多对多关系。我有一个覆盖 get_queryset 方法的 View 。在我的报道报告中，这种方法是我唯一的失误。我正在寻找有关如何为此方法编写单元测试的指导。感谢您抽出时间回答我的问题。

模型.py

from django.db import models 
from django.template.defaultfilters import slugify 
from django.urls import reverse 

class Technologies(models.Model): 

    name = models.CharField(max_length=64, unique=True) 
    slug = models.SlugField() 

    def __str__(self): 
        return self.slug 

    def save(self, *args, **kwargs): 
        self.slug = slugify(self.name) 
        super(Technologies, self).save(*args, **kwargs) 

class Project(models.Model): 

    title = models.CharField(max_length=64) 
    description = models.CharField(max_length=128) 
    repo = models.URLField() 
    slug = models.SlugField() 

    image = models.ImageField( 
            upload_to='project_images', 
            default='project_images/default_project.png') 
    technologies = models.ManyToManyField(Technologies) 

    def __str__(self): 
        return self.title 

    def save(self, *args, **kwargs): 
        self.slug = slugify(self.title) 
        super(Project, self).save(*args, **kwargs) 

    def get_absolute_url(self): 
        return reverse("projects:detail", kwargs={"slug": self.slug}) 

View .py

from django.views.generic import DetailView, ListView 
from .models import Project 

class ProjectsListView(ListView): 

    model = Project 

class ProjectDetailView(DetailView): 

    model = Project 

class TechnologiesListView(ListView): 

    model = Project 
    allow_empty = False  # If list is empty 404 

    def get_queryset(self): 

        return Project.objects.filter(technologies__slug=self.kwargs['slug']) 

网址.py

from django.urls import path 
from . import views 

   app_name = "projects" 
   urlpatterns = [ 

        path('', view=views.ProjectsListView.as_view(), name='list'), 
        path('<slug>', view=views.ProjectDetailView.as_view(), name='detail'), 
        path('tagged/<slug>', view=views.TechnologiesListView.as_view(), name='tech_list'), 

    ] 

所以我的问题是这个方法:

def get_queryset(self): 

    return Project.objects.filter(technologies__slug=self.kwargs['slug']) 

测试 View .py

import pytest
from django.test import RequestFactory
from django.urls import reverse
from mixer.backend.django import mixer

from projects.views import ProjectDetailView, ProjectsListView, TechnologiesListView


@pytest.mark.django_db
class TestProjectViews:

    def test_projects_by_technologies_view(self):
        tech = mixer.blend('projects.Technologies')
        path = reverse('projects:tech_list', kwargs={'slug': tech.slug})
        request = RequestFactory().get(path)
        response = TechnologiesListView.as_view()(request)
        assert response.status_code == 200, 'Should be status code 200'

当我运行这个测试时，我得到:

    def get_queryset(self):
>       return Project.objects.filter(technologies__slug=self.kwargs['slug'])
E       KeyError: 'slug'

这是因为 kwargs 不在请求工厂生成的请求中吗？或者这是一个数据库问题？我对此非常迷茫和困惑，非常感谢任何明智的话。

Answer 1

写出您的问题可以更好地分解问题，这真是令人惊讶。这是我的解决方案。

def test_projects_by_technologies_view(self):
    self.tech = mixer.blend('projects.Technologies')
    self.proj = mixer.blend(Project, technologies=self.tech)
    self.path = reverse('projects:tech_list', kwargs={'slug': self.tech.slug})
    self.request = RequestFactory().get(self.path)
    self.response = TechnologiesListView.as_view()(self.request, slug=self.tech.slug)
    assert self.response.status_code == 200, 'Should be status code 200'