python - 启动 HTTP/HTTPS 服务器，python -m SimpleHTTPServer

Question

我试图在我的本地主机上启动 HTTPS 服务器，但出现以下错误。我以管理员身份打开cmd。

C:\Windows\system32>python -m SimpleHTTPServer
Traceback (most recent call last):
  File "C:\Python27\lib\runpy.py", line 162, in _run_module_as_main
    "__main__", fname, loader, pkg_name)
  File "C:\Python27\lib\runpy.py", line 72, in _run_code
    exec code in run_globals
  File "C:\Python27\lib\SimpleHTTPServer.py", line 224, in <module>
    test()
  File "C:\Python27\lib\SimpleHTTPServer.py", line 220, in test
    BaseHTTPServer.test(HandlerClass, ServerClass)
  File "C:\Python27\lib\BaseHTTPServer.py", line 595, in test
    httpd = ServerClass(server_address, HandlerClass)
  File "C:\Python27\lib\SocketServer.py", line 419, in __init__
    self.server_bind()
  File "C:\Python27\lib\BaseHTTPServer.py", line 108, in server_bind
    SocketServer.TCPServer.server_bind(self)
  File "C:\Python27\lib\SocketServer.py", line 430, in server_bind
    self.socket.bind(self.server_address)
  File "C:\Python27\lib\socket.py", line 224, in meth
    return getattr(self._sock,name)(*args)
socket.error: [Errno 10013] An attempt was made to access a socket in a way forb
idden by its access permissions

Answer 1

您的 Windows 防火墙可能会阻止 python 监听。另外，尝试在命令行中添加一个高于 1024 的不同端口号，看看是否有帮助。