javascript - 在 javascript/jquery 中具有参数的函数将不起作用

Question

我的函数中有值，但它说它尚未定义。

这是我的代码:

<img onload="getFullnameDetails(263,225)" src="'+getBaseURL()+'js/check/no-image.png" rel="fullname" />

function getFullnameDetails(mainHeight,upperstyle){
setTimeout("fullnameCenter(mainHeight,upperstyle)",2000);
}

function fullnameCenter(mainHeight,upperstyle){
    var distOfMainAndUpper = 38;
    var mainHalfHeight = 131.5;
    var imageHeight = jQuery("img[rel='fullname']").height(); //there is a delay
    var imageHalfHeight = imageHeight/2;
    var fromImageTopToMainHalf = mainHalfHeight - imageHeight;
    var position = imageHalfHeight+fromImageTopToMainHalf-distOfMainAndUpper;
    jQuery(".test1").css("bottom",position+"px");
}

这里说 mainHeight 没有定义。为什么会出现这种情况。这发生在这一行: setTimeout("fullnameCenter(mainHeight,upperstyle)",2000);

提前致谢;)

Answer 1

试试这个

function getFullnameDetails(mainHeight,upperstyle){
    setTimeout(function() {fullnameCenter(mainHeight,upperstyle);},2000);
}