python - 从 Python 中的除法中打印 %

Question

我用下面的方法来产生百分比:

L = ['aa', 'bb']

for row, each in enumerate(l):
    percent = float(row)/150 * 100
    print "{0:.0f}%".format(percent)

我想要的是分别具有“0%”和“0.67%”，但它给出“0%”和“1%”。

我该如何纠正它？

Answer 1

来自官方 documentation :

'f' - Fixed point. Displays the number as a fixed-point number. The default precision is 6.

...

The precision is a decimal number indicating how many digits should be displayed after the decimal point for a floating point value formatted with 'f' and 'F',..

所以你可以说出小数点后有多少位数字。

>>> "{0:.2f}%".format(123.4567)
'123.46%'
>>> 
>>> "{0:.5f}%".format(123.4567)
'123.45670%'

因此将其更改为:"{0:.2f}%".format(percent) 并且您的 for 循环行中还有一个拼写错误，它应该是 enumerate(L )

L = ['aa', 'bb']

for row, each in enumerate(L):
    percent = float(row)/150 * 100
    print "{0:.2f}%".format(percent)

打印

0.00%
0.67%