javascript - Jasmine 的错误方法http测试( Angular 7)

Question

我在 Angular 7 中有一个简单的应用程序，它使用 giphy api 发出 gif 列表请求，通知 gif 的数量和搜索词。

我想创建一个发出请求的测试，并验证 gif 列表的结果是否大于 0。

但是我有很多错误而且我不明白为什么

服务

private apiKey:string = "123";
private shortUrl:string = "//api.giphy.com/v1/gifs/search?q="

searchGif(term:string, limit:number):Observable<Gif[]> {
     let url:string = this.getUrl(term, limit);
     return  this.http.get<Gif[]>(`${url}/`);
}

测试

let service: GifSearchService;
let httpMock: any
let limit: number = 1;
let term: string = "dogs";

beforeEach(() => {
    httpMock = jasmine.createSpyObj('http', [ 'get', 'post' ]);
    service = new GifSearchService(httpMock);
});

it('Should return value when search for gifs', () => {
    let result = service.searchGif(term, limit);
    expect(result.length).toBeGreaterThan(0);
  });

错误

ERROR in node_modules/rxjs/internal/Observable.d.ts(14,60): error TS1183: An implementation cannot be declared in ambient contexts. src/app/gif-list/gif-list.component.spec.ts(33,19): error TS2339: Property 'length' does not exist on type 'Observable'.

Answer 1

我认为唯一有意义的测试是测试它是否返回一个 Observable...就像这样..

expect(results).toEqual(jasmine.any(Observable))