python - 通过字典访问函数

Question

我有这样一个函数:

def abc(a,b):
    return a+b

我想将它分配给这样的字典:

functions = {'abc': abc(a,b)}

问题是，当把它赋给字典时，由于参数还没有定义，我得到了错误:

NameError: name 'a' is not defined

我会做显而易见的事情并提前定义参数，但我需要在循环中定义它们(然后根据在列表中的定位来调用函数)，如下所示:

functions_to_call = ['abc']
for f in functions_to_call:
    a=3
    b=4
#This is supposed to locate and run the function from the dictionary if it is in the list of functions.
    if f in functions:
       functions[f] 

Answer 1

I need to define them in a loop (and then call the function based on locating it in a list)

那么简单地将函数对象保存在字典中有什么问题:

functions = {'abc':abc}

和然后在循环时将a和b应用于函数:

functions_to_call = ['abc']
for f in functions_to_call:
    a, b = 3, 4
    if f in functions:
       functions[f](a, b)