python - 如何为我的数据集创建多线图？

Question

我有以下 pandas DataFrame df:

df = pd.DataFrame(columns=["Event1", "Event2", "Event3"], 
                                data=[[15,1,22],
                                      [16,1.26,80],
                                      [27,0,15]])

df = df.set_index([["Series1", "Series2", "Series3"]])

我想创建一个 X 轴包含 Event1、Event2 和 Event3 的多线图，而 Y 轴应该是相应的数值值(value)。应该有 3 个系列:Series1、Series2、Series3。

如何在 sns.pointplot(x=???, y=? ??, hue=???,data=df)?

plt.figure(figsize=(12,8))
ax = sns.pointplot(x=???, y=???, hue=???,data=df)
ax.grid(b=True, which='major', color='#d3d3d3', linewidth=1.0)
ax.grid(b=True, which='minor', color='#d3d3d3', linewidth=0.5)
plt.show()

Answer 1

将数据透视表 df 重组为经典数据框并根据需要绘制:

import matplotlib.pylab as plt
import pandas as pd
import seaborn as sns

df = pd.DataFrame(columns=["Event1", "Event2", "Event3"], 
                                data=[[15,1,22],
                                      [16,1.26,80],
                                      [27,0,15]])
df = df.set_index([["Series1", "Series2", "Series3"]])
print(df)

# reorganize df to classic table
df2=df.stack().reset_index()
df2.columns = ['Series','Event','Values']
print(df2)

plt.figure(figsize=(12,8))
ax = sns.pointplot(x='Event', y='Values', hue='Series',data=df2)
ax.grid(b=True, which='major', color='#d3d3d3', linewidth=1.0)
ax.grid(b=True, which='minor', color='#d3d3d3', linewidth=0.5)
plt.show()

df2:

    Series   Event  Values
0  Series1  Event1   15.00
1  Series1  Event2    1.00
2  Series1  Event3   22.00
3  Series2  Event1   16.00
4  Series2  Event2    1.26
5  Series2  Event3   80.00
6  Series3  Event1   27.00
7  Series3  Event2    0.00
8  Series3  Event3   15.00