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php - 使用ajax发送特殊字符并正确接收它们到php

转载 作者:行者123 更新时间:2023-11-28 21:03:30 24 4
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我有一个 javascript 函数,它获取一些参数数据并尝试将它们保存在 postgreSQL 数据库中。这是javascript ajax函数

function insertCalendarEvents(calendar_group, event_name, event_datestart, event_datestop, event_timestart, event_timestop, event_info, onfinish) {
var request;
if(window.XMLHttpRequest)
request = new XMLHttpRequest();
else
request = new ActiveXObject("Microsoft.XMLHTTP");

request.onreadystatechange = function() {
if (request.readyState == 4 && request.status == 200) {alert(request.responseText);
if(request.responseText.substr(0, 6) == "error ")
alert(errorName[request.responseText.substr(6)]);
else {
var event_id = 7;
onfinish(event_id);
}
}
}

var params = "action=insertCalendarEvents&calendar_group=" + calendar_group + "&event_name=" + encodeURIComponent(event_name) + "&event_datestart=" + event_datestart + "&event_datestop=" + event_datestop + "&event_timestart=" + event_timestart + "&event_timestop=" + event_timestop + "&event_info=" + event_info;
request.open("GET", "php/calendar.php?" + params, true);
request.setRequestHeader("If-Modified-Since", "Sat, 1 Jan 2000 00:00:00 GMT");
request.setRequestHeader("Content-type", "application/x-www-form-urlencoded; charset=UTF-8");
request.send();
}

这是 php 函数:

if($action == "insertCalendarEvents") {
$calendar_group = $_GET["calendar_group"];
$event_name = "'" . htmlspecialchars(urldecode($_GET["event_name"])) . "'";
$event_datestart = "'" . $_GET["event_datestart"] . "'";
$event_datestop = "'" . $_GET["event_datestop"] . "'";
$event_timestart = $_GET["event_timestart"] != "" ? "'" . $_GET["event_timestart"] . "'" : "null";
$event_timestop = $_GET["event_timestop"] != "" ? "'" . $_GET["event_timestop"] . "'" : "null";
$event_info = "'" . $_GET["event_info"] . "'";
echo $event_name;

require_once("connect.php");
$query = "INSERT INTO calendar_events (calendar_group, event_name, event_datestart, event_datestop, event_timestart, event_timestop, event_info) VALUES (" . $calendar_group . ", " . $event_name . ", " . $event_datestart . ", " . $event_datestop . ", " . $event_timestart . ", " . $event_timestop . ", " . $event_info . ")";
$result = pg_query($connect, $query);
if(!$result)
die("error 1"); // query error

$query = "SELECT currval('events_event_id_seq')";
$result = pg_query($connect, $query);
if(!$result)
die("error 1"); // query error

$row = pg_fetch_row($result);
echo $row[0];
}

问题是当我尝试添加特殊字符(现在我仅在 event_name 参数上测试)时,例如 + 或换行符,因此它不起作用,在 + 上它用空格替换它,换行符不执行任何操作。

最佳答案

在发送到服务器之前对数据进行编码

我也遇到了像你现在这样的问题,但我实现的这个功能解决了我的问题

 function encode(val){
var eVal;
if(!encodeURIComponent){
eVal=escape(val);
eVal=eVal.replace(/@/g,"%40");
eVal=eVal.replace(/\//g,"%2F");
eVal=eVal.replace(/\+/g,"%2B");
eVal=eVal.replace(/'/g,"%60");
eVal=eVal.replace(/"/g,"%22");
eVal=eVal.replace(/`/g,"%27");
eVal=eVal.replace(/&/g,"%26");
}else{
eVal=encodeURIComponent(val);
eVal=eVal.replace(/~/g,"%7E");
eVal=eVal.replace(/!/g,"%21");
eVal=eVal.replace(/\(/g,"%28");
eVal=eVal.replace(/\)/g,"%29");
eVal=eVal.replace(/'/g,"%27");
eVal=eVal.replace(/"/g,"%22");
eVal=eVal.replace(/`/g,"%27");
eVal=eVal.replace(/&/g,"%26");
}
return eVal.replace(/\%20/g,"+");
}

关于php - 使用ajax发送特殊字符并正确接收它们到php,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10448060/

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