python如果多个字符串返回句子中包含的单词

Question

我有一个单词列表，我想做 if 语句，下面是我的列表:

list = ['camera','display','price','memory'(will have 200+ words in the list)]

这是我的代码:

def check_it(sentences):
    if 'camera' in sentences and 'display' in sentences and 'price' in sentences:
        return "Camera/Display/Price"
    if 'camera' in sentences and 'display' in sentences:
        return "Camera/Display"
    ...
    return "Others"

h.loc[:, 'Category'] = h.Mention.apply(check_it)

这些组合太多了，我也想让单词单独返回行。有谁知道如何制作这个样本并单独返回单词而不是做“相机/显示器/价格”？

Answer 1

使用str.findall通过正则表达式 - 使用 | 加入列表的所有值，最后一个 str.join / 的值:

df = pd.DataFrame({'Mention':['camera in sentences and display in sentences',
                              'camera in sentences price']})


L = ['camera','display','price','memory']
pat = '|'.join(r"\b{}\b".format(x) for x in L)
df['Category'] = df['Mention'].str.findall(pat).str.join('/')
print (df)
                                        Mention        Category
0  camera in sentences and display in sentences  camera/display
1                     camera in sentences price    camera/price

另一种列表理解的解决方案，也适用于带有 join 的列表使用生成器:

df['Category1'] = [[y for y in x.split() if y in L] for x in df['Mention']]
df['Category2'] = ['/'.join(y for y in x.split() if y in L) for x in df['Mention']]
print (df)
                                        Mention          Category1  \
0  camera in sentences and display in sentences  [camera, display]   
1                     camera in sentences price    [camera, price]   

        Category2  
0  camera/display  
1    camera/price