javascript - 获取对象的复杂属性值

Question

给定这样的 json :

{ "rss": {
   "page": 1,
   "results": [{
      "type": "text",
      "$": 10
   }],
   "text": [{
      "content": "Lorem ipsum dolor sit amet.",
      "author": {
         "name": "Cesar",
         "email": "cesar@evoria.com"
      },
   },
   {
      "content": "Tema Tis rolod muspi merol.",
      "author": {
         "name": "Cleopatre",
         "email": "cleopatre@pyramid.com"
      },
   }]
}

在 javascript 中，我可以像这样检索值:

var json = JSON.parse(datajson);
$.each(json.text, function(key, val) {
    // this one is ok
    var content = val['content'];
    // this one does not work
    var authorname = val['author.name'];
});

这是一种在给定字符串格式的属性名称的情况下检索复杂对象的值的方法，例如 json.text[0].author.name？

编辑我想将所需的属性存储在另一个对象中，例如:

[
    { dt: "Text content", dd: "content" },
    { dt: "Author name", dd: "author.name"}
]

Answer 1

您可以按 分割“索引”。 并循环遍历“段”，在每次迭代中按级别递减。

var obj = {
   author : {
      name : "AuthorName"
   }
}

function get_deep_index(obj, index) {   
   var segments = index.split('.')
   var segments_len = segments.length
   var currently_at = obj
   for(var idx = 0; idx < segments_len; idx++) {
      currently_at = currently_at[segments[idx]]
   }
   return currently_at
}

console.log(get_deep_index(obj, 'author.name'))