Python 循环(在列表中的 dermined 位置插入项目)

Question

我有这个代码:

number = 2
size = 5
list_b = [("b","b","b")]
list_a = [("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a"),("a","a","a")]
for i in range(number):
   list_a.insert(size,list_b)
print list_a

它给了我这个:

[('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('b', 'b', 'b'),
('b', 'b', 'b'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a')]

基本上，它在 size 定义的位置插入 2 倍的 list_b

我想要一个 self 重复的循环，以便 list_b 插入 number 中定义的次数，但重复 size 次。很难解释，所以这是我想要的结果:

[('a', 'a', 'a'),
('a', 'a', 'a'), 
('a', 'a', 'a'),
('a', 'a', 'a'), 
('a', 'a', 'a'), 
('b', 'b', 'b'), 
('b', 'b', 'b'), 
('a', 'a', 'a'), 
('a', 'a', 'a'), 
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('b', 'b', 'b'),
('b', 'b', 'b'),
('a', 'a', 'a'),
('a', 'a', 'a'), 
('a', 'a', 'a'), 
('a', 'a', 'a'),
('a', 'a', 'a'),
('b', 'b', 'b'),
('b', 'b', 'b'), 
('a', 'a', 'a'), 
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('b', 'b', 'b'),
('b', 'b', 'b'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('a', 'a', 'a'),
('b', 'b', 'b'),
('b', 'b', 'b'),...and so on]

编辑

如果我有这个:

 list_a = [a, ] * 15
 list_b = [b,]
 s = 5
 n = 2

我想得到这个:

 [b,b,a,a,a,a,a,b,b,b,b,a,a,a,a,a,b,b,b,b,a,a,a,a,a,b,b]

由于这是一个示例，list_a、s 和 n 会有所不同，我如何在一个或两个循环中执行此操作？

谢谢，

法沃拉斯

Answer 1

为了论证，我将调用 ('a', 'a', 'a') => a 和 ('b', 'b' , 'b') => b.

number=2
size=5
list_a=["a"]*20
list_b=["b"]

workfor=len(list_a)+(len(list_a)/size)*number*len(list_b)
i=0
while i<workfor:
    i+=size
    for times in range(number):
        for elem in list_b:
            list_a.insert(i,elem)
        i+=len(list_b)

print list_a

结果在 =>

 ['a', 'a', 'a', 'a', 'a', 'b', 'b', 'a', 'a', 'a', 'a', 'a', 'b', 'b', 'a', 'a', 'a', 'a', 'a', 'b', 'b', 'a', 'a', 'a', 'a', 'a', 'b', 'b']