php - jQuery 发布和获取表单数据

Question

提交表单后，我可以使用 $_POST 获取其字段值。但是，我正在尝试使用基本的 jQuery(没有任何插件)来检查是否有任何字段为空白，我只想在没有任何空白字段的情况下发布表单内容。

我正在尝试下面的代码，并且我使用 jQuery 取得了成功，但唯一的问题是我在使用 jQuery 检查后无法发布表单。它不会在 jQuery 之后到达 $_POST。

此外，如何在 jQuery 中获取服务器响应(以检查是否存在任何服务器错误)。这是我正在尝试的:

HTML:

<form action="" id="basicform" method="post">
    <p><label>Name</label><input type="text" name="name" /></p>
    <p><label>Email</label><input type="text" name="email" /></p>  

    <input type="submit" name="submit" value="Submit"/>
</form>

jQuery:

jQuery('form#basicform').submit(function() {
    //code
    var hasError = false;

    if(!hasError) {
            var formInput = jQuery(this).serialize();
            jQuery.post(jQuery(this).attr('action'),formInput, function(data){

            //this does not post data
            jQuery('form#basicform').slideUp("fast", function() {
                    //how to check if there was no server error.
                });
            });
        }               
    return false;


});

PHP:

if(isset($_POST['submit'])){
    $name = trim($_POST['name'];
    $email = trim($_POST['email'];  

    //no any error
    return true;
}

Answer 1

要非常具体地回答这个问题:

How can I get the server response back in the jQuery (to check if there was any server error or not). Here's what I'm trying:

听起来就像您在谈论通过 jQuery-Ajax 进行服务器端验证。

那么你需要:

• 将变量的 JavaScript 值发送到 PHP
• 检查是否有错误发生
• 将结果发送回 JavaScript

所以你是说，

However, I am trying to use a basic jQuery (without any plugin) to check if any field was blank, I want to post the form content only if there's no any blank field.

JavaScript/jQuery 代码:

看一下这个例子:

<script>
$(function()) {
    $("#submit").click(function() {
        $.post('your_php_script.php', {
             //JS Var   //These are is going to be pushed into $_POST
             "name"   : $("#your_name_field").val(),
             "email"  : $("#your_email_f").val()
        }, function(respond) {
           try {
               //If this falls, then respond isn't JSON 
               var result = JSON.parse(respond);

               if ( result.success ) { alert('No errors. OK')  }
           } catch(e) {
               //So we got simple plain text (or even HTML) from server
               //This will be your error "message" 
               $("#some_div").html(respond);
           }
       });
   });
}
</script>

好吧，现在不是看 php one 的时候了:

<?php

/**
 * Since you're talking about error handling
 * we would keep error messages in some array
 */

$errors = array();

function add_error($msg){
  //@another readers 
  //s, please don't tell me that "global" keyword makes code hard to maintain
  global $errors;
  array_push($errors, $msg);
}

/**
 * Show errors if we have any
 * 
 */
function show_errs(){
   global $errors;
   if ( !empty($errors) ){

     foreach($errors as $error){
        print "<p><li>{$error}</li></p>";
     }
     //indicate that we do have some errors:
     return false;
   }
  //indicate somehow that we don't have errors
  return true;
}



function validate_name($name){
  if ( empty($name) ){
     add_error('Name is empty');   
  }

  //And so on... you can also check the length, regex and so on
  return true;
}


//Now we are going to send back to JavaScript via JSON 

if ( show_errs() ){
   //means no error occured

   $respond = array();
   $respond['success'] = true;
   //Now it's going to evaluate as valid JSON object in javaScript
   die( json_encode($respond) );

} //otherwise some errors will be displayed (as html)